我想启动开始时一个按钮pssed第一$ P $结束时，它被释放（基本上我想衡量一个按钮的时间长短下降）的定时器。我将使用System.nanoTime（）方法，在这两个时间，然后减去初始数量从最后一节以获取经过，而按钮被按住的时间的测量。

I would like to start a timer that begins when a button is first pressed and ends when it is released (basically I want to measure how long a button is held down). I'll be using the System.nanoTime() method at both of those times, then subtract the initial number from the final one to get a measurement for the time elapsed while the button was held down.

（如果您有使用其他的东西比nanoTime（）或测量按钮的时间长短下来的一些其他的方式有什么建议，我是开放给那些为好。）

(If you have any suggestions for using something other than nanoTime() or some other way of measuring how long a button is held down, I'm open to those as well.)

谢谢！ 刘德华

推荐答案

我觉得这样的事情应该工作：（主要用它代替OnClickListener OnTouchListener）

I think something like this should work: (basically use OnTouchListener instead of OnClickListener)

// this goes somewhere in your class:
  long lastDown;
  long lastDuration;

  ...

  // this goes wherever you setup your button listener:
  button.setOnTouchListener(new OnTouchListener() {
     @Override
     public boolean onTouch(View v, MotionEvent event) {
        if(event.getAction() == MotionEvent.ACTION_DOWN) {
           lastDown = System.currentTimeMillis();
        } else if (event.getAction() == MotionEvent.ACTION_UP) {
           lastDuration = System.currentTimeMillis() - lastDown;
        }
     }
  };