$(document).ready(function() {
    $("#list1").jqGrid({
        url: 'example1.php',
        /*balabala...*/
        gridComplete: function() {

        }
    });

    $("#list2").jqGrid({
        url: 'example2.php',
        /*balabala...*/
        gridComplete: function() {

        }
    });

    /*I want to do something here, but the above grids must be both complete first.*/
    Something...
});

我应该怎么办？谢谢！

How should I do ? Thanks!

推荐答案

最简单的方法就是把你的东西在 gridComplete 回调，但有两个回调检查该另一个已完成。这些方针的东西：

The easiest way is to put your "something" in the gridComplete callbacks but have the two callbacks check that the other one has finished. Something along these lines:

function do_something_wonderful() {
    // This is the awesome stuff that you want to
    // execute when both lists have loaded and finished.
    // ...
}

var one_done = false;
function done_checker() {
    if(one_done) {
        // The other one is done so we can get on with it.
        do_something_wonderful();
    }
    one_done = true;
}

$("#list1").jqGrid({
    //blah blah blah
    gridComplete: done_checker
});
$("#list2").jqGrid({
    //blah blah blah
    gridComplete: done_checker
});

这很好地扩展到两个以上的名单与一对夫妇的小改动：

This nicely extends to more than two lists with a couple small modifications:

普通版看起来有点像这样的：

The general version would look sort of like this:

var number_of_tasks = 11; // Or how many you really have.
var how_many_done   = 0;
function done_checker() {
    ++how_many_done;
    if(how_many_done == number_of_tasks) {
        // All the AJAX tasks have finished so we can get on with it.
        do_something_wonderful();
    }
}

这是更好的版本将包裹的状态下封闭：

An even better version would wrap up the state in a closure:

var done_checker = (function(number_of_tasks, run_when_all_done) {
    var how_many_done = 0;
    return function() {
        ++how_many_done;
        if(how_many_done == number_of_tasks) {
            // All the AJAX tasks have finished so we can get on with it.
            run_when_all_done();
        }
    }
})(do_something_wonderful, 11);