我们有followig code：

We have the followig code:

[Serializable]
public class Class1
{
    [XmlElement("description")]
    public string Description { get; set; }
}
class Program
{
    static void Main(string[] args)
    {
        var list = new List<Class1> {new Class1() {Description = "Desc1"}, new Class1() {Description = "Desc2"}};
        var serializer = new XmlSerializer(typeof(List<Class1>), new XmlRootAttribute("root"));
        var ms = new MemoryStream();
        serializer.Serialize(ms, list);
        ms.Position = 0;
        var result = new StreamReader(ms).ReadToEnd();
    }
}

执行后，我们将在'结果'变量如下：

after execution we will have the following in 'result' variable:

<?xml version="1.0"?>
<root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <Class1>
    <description>Desc1</description>
  </Class1>
  <Class1>
    <description>Desc2</description>
  </Class1>
</root>

现在的问题是：如何从1级更改XML元素的名称为项目1不改变类的名称

The question is: how to change xml elements name from 'Class1' to 'Item1' without changing class name?

推荐答案

您可以使用XmlTypeAttribute.TypeName对于这一点。

You can use XmlTypeAttribute.TypeName for this.

试试这个为你 1级定义

    [XmlType(TypeName = "Item1")]
    [Serializable]
    public class Class1
    {
        [XmlElement("description")]
        public string Description { get; set; }
    }