现在我想火寻找一个AJAX。之后我的$ HTTP（可能是$国土资源只是AJAX）的成功，我需要更新index.page用户界面视图显示结果。这里是我的code：

angular.module('ecom').config(['$stateProvider','$urlRouterProvider',function($stateProvider,$urlRouterProvider){    //任何无与伦比的网址，发送到/仪表板    $ urlRouterProvider.otherwise（/仪表板）;    $ stateProvider     .STATE（家，             {            网址：'/家，            templateUrl：提交的/ home / home.html做为             }）      .STATE（'费用'，              {            网址：'/费'，            templateUrl：提交/支出/支出-list.html'，            控制器：'SubmitterExpensesCtrl              }）        .STATE（'收据'，              {            网址：'/收据，            templateUrl：提交/收据/ receipts.html              }）        .STATE（设置，             {            网址：/设置            templateUrl：设置/ settings.html'，            控制器：'SettingCtrl             }）        .STATE（'注销'，              {            网址：'/注销，            templateUrl：'注销/ logout.html'，            控制器：'LogoutCtrl              }）        .STATE（信息搜索结果'，                {            网址：'/信息搜索结果'，            templateUrl：ExpenseResult / searchresult.html'，            控制器：'resultCtrl                }）}]）;这是index.page：＆LT; NAV＆GT;＆LT;搜索和GT;＆LT; /搜索＆GT;＆LT; / NAV＆GT; //当点击搜索，就会触发一个Ajax调用，我将结果显示在searchresult.html＆LT; D​​IV CLASS =身体容器＆GT;        ＆LT; D​​IV CLASS =COL-MD-1＆GT;＆LT; / DIV＆GT;        ＆LT; D​​IV CLASS =集装箱APP-包装COL-MD-12的UI视图＆gt;＆LT; / DIV＆GT; //主要内容将显示在这里。        ＆LT; D​​IV CLASS =COL-MD-1＆GT;＆LT; / DIV＆GT;    ＆LT; / DIV＆GT;＆LT;页脚和GT;＆LT; /页脚＆GT;

我如何更改网址/结果，并在索引页显示searchresult.html？我可以尝试$ location.path（'/信息搜索结果'）在阿贾克斯seccuee方法？

解决方案

注入$状态到控制器中，并调用$ state.go（Statename的），一旦$ HTTP / $资源调用返回的承诺。

所以你的情况，类似...

  $ http.post（/ AJAX）。然后（功能（数据，状态，头，配置）{    $ state.go（信息搜索结果）;}） 

Now I am trying to fire a ajax for search. after I $http( may be $resourse just ajax) success, I need to update the ui-view in index.page to show the result. Here is my code:

angular.module('ecom').config(['$stateProvider','$urlRouterProvider',function($stateProvider,$urlRouterProvider){
    //for any unmatched url,send to /dashboard
    $urlRouterProvider.otherwise("/dashboard");
    $stateProvider
     .state('home',
             {
            url:'/home',
            templateUrl:'submitter/home/home.html'
             }) 
      .state('expenses',
              {
            url:'/expenses',
            templateUrl:'submitter/expenses/expense-list.html',
            controller:'SubmitterExpensesCtrl'
              })
        .state('receipts',
              {
            url:'/receipts',
            templateUrl:'submitter/receipts/receipts.html'
              })
        .state('settings',
             {
            url:'/settings',
            templateUrl:'settings/settings.html',
            controller:'SettingCtrl'
             })
        .state('logout',
              {
            url:'/logout',
            templateUrl:'logout/logout.html',
            controller:'LogoutCtrl'
              })
        .state('searchResult',
                {
            url:'/searchresult',
            templateUrl:'ExpenseResult/searchresult.html',
            controller:'resultCtrl'     
                })
}]);
This is index.page :
<nav><search></search></nav> // When click search, it will fire a ajax call, I will display the result in searchresult.html
<div class="body-container">
        <div class="col-md-1"></div>
        <div class="container app-wrapper col-md-12" ui-view></div> //the main content will display here.
        <div class="col-md-1"></div>
    </div>
<footer></footer>

How can I change the url to /result and display the searchresult.html in of index page? Can I try $location.path('/searchresult') in ajax seccuee method?;

解决方案

Inject $state into your controller and call $state.go(statename) once the $http/$resource call has returned the promise.

So in your case, something like...

$http.post("/ajax")
.then(function(data, status, headers, config) {
    $state.go("searchResult");
})