我是新来的量角器，我想写一个测试，看看有没有美女主播与网址给404错误。

I'm new to protractor, I want to write a test to see that there are no anchors with urls giving 404 errors.

我已经看到了这个如何测试用量角器HTML链接？，但对于只有一个确定的环节，我想这样做在页面所有链接。

I've seen this How to test html links with protractor?, but is for one determined link only, I want to do it for all links in the page.

测试应该通过对HTTP状态200，这里How用量角器获得响应状态code和响应文本？

The test should pass for the http status 200, as stated here How to use protractor to get the response status code and response text?

我有两个问题：

推荐答案

我认为它肯定是可行的，并会使情理之中的事情，如果范围是有限的，因为这不是一个典型的UI测试硒的webdriver的用途。你可以做这样的事情，找到所有环节，得到下面的网址和消防使用像申请模块的GET请求。这里是一个伪code。

I think its definitely doable and would make sense to do it if the scope is limited since this is not a typical UI test that selenium-webdriver is used for. You could do something like, find all links, get underneath url and fire a GET request using a module like request. Here is a pseudo code.

var request = require('request');
var assert = require('assert');
element.all(by.tagName('a')).then(function(link) {
   var url = link.getAttribute('href');
   if(url) {
       request(url, function (error, response, body) {
           assert.equal(response.statusCode, 200, 'Status code is not OK');
       });
    }
});