这是我的code，Eclipse不显示任何错误，程序工作正常，但它根本没有做什么，我想:)

here's my code, Eclipse doesn't show any errors, program's working fine, but it simply doesn't do exactly what i want:)

    View image_view_danger_rate = (ImageView) findViewById(R.id.origin);
    View image_view_origin = (ImageView) findViewById(R.id.danger_rate);

    String entry_tag = (String) descriptionResultView.findViewById(resID).getTag();

    String dangerous = "dangerous";
    String not_dangerous = "not_dangerous";

    if ( entry_tag == dangerous) {
        image_view_danger_rate.setBackgroundResource(R.drawable.attention);
    }else if ( entry_tag == not_dangerous) {
        image_view_danger_rate.setBackgroundResource(R.drawable.its_ok);
        image_view_origin.setBackgroundResource(R.drawable.artificial);
    }

应用程序应该两幅图像之间进行选择弹出屏幕上，这取决于存储在XML文件中的标签。 因此，如果标签写着危险，则应该显示的关注 - 图像。 如果标签说：not_dangerous，应该是its_ok - 图像。

The application should choose between two images to pop-up on the screen, depending on a tag stored in the xml file. So, if the tag says "dangerous", then should be shown the "attention"-image. If the tag says "not_dangerous", there should be the "its_ok"-image.

现在，如果没有的话，比较显示的图像完美的作品。

Now, displaying the images without an if-comparison works perfectly.

如果我打印出来的标签，一个字符串，它的工作原理，它打印正确的危险或not_dangerous，根据不同的标签。

If i print out the tags as a string, it works, it prints correctly "dangerous" or "not_dangerous", depending on the tag.

但是，如果有，如上图所示，如果一个对比，没有任何反应，无图像显示。

But if there's a if-comparison as shown above, nothing happens, no image is shown.

请人帮助！=）

推荐答案

使用 string1.equalsIgnoreCase（东西）或 .equals（某事）;

使用 == （字符串）在Java中你是比较它们的相同的参考。像你这样的测试，如果他们两个都是字符串对象。

With == (for strings) in java you are comparing they are of same reference. Like you did is the test if both of them are strings objects.