我有这块code，我想缩短...

  PackageManager P = context.getPackageManager（）;
    最后的名单，其中，PackageInfo＆GT; appinstall = p.getInstalledPackages（PackageManager.GET_PERMISSIONS）;
    PackageManager亲= context.getPackageManager（）;
    最后的名单，其中，PackageInfo＆GT; apllprovides = pro.getInstalledPackages（PackageManager.GET_PROVIDERS）;
 

我是认真恼火做到这一点一再增加新标志的权限，我需要做几次，有没有，我可以把所有的国旗相同的定义更短的方法... ???

让我这么说吧，我能做到这一点？？？？ （当然这给出了一个错误，但类似的东西..）

  PackageManager P = context.getPackageManager（）;
    最后的名单，其中，PackageInfo＆GT; appinstall = p.getInstalledPackages（PackageManager.GET_PERMISSIONS）.addFlag（PackageManager.GET_PROVIDERS）;
 

解决方案

如果它是相同的语法，C＃和标志设置是否正确，你可以这样做：

  PackageManager P = context.getPackageManager（）;
最后的名单，其中，PackageInfo＆GT; appinstall =
    p.getInstalledPackages（PackageManager.GET_PERMISSIONS |
                                      PackageManager.GET_PROVIDERS）
 

I have this piece of code that I would like to shorten...

    PackageManager p = context.getPackageManager();
    final List<PackageInfo> appinstall = p.getInstalledPackages(PackageManager.GET_PERMISSIONS);
    PackageManager pro = context.getPackageManager();
    final List<PackageInfo> apllprovides = pro.getInstalledPackages(PackageManager.GET_PROVIDERS);

I am seriously irritated to do this again and again to add new flag permissions, and I need to do it a couple of times, is there a shorter method in which I could put all the flags on the same definition...???

Let me put it this way, can I do this...??? (of course this gives an error, but something similar..)

    PackageManager p = context.getPackageManager();
    final List<PackageInfo> appinstall = p.getInstalledPackages(PackageManager.GET_PERMISSIONS).addFlag(PackageManager.GET_PROVIDERS);

If it's the same syntax as C# and the flags are set properly, you could do this:

PackageManager p = context.getPackageManager(); 
final List<PackageInfo> appinstall = 
    p.getInstalledPackages(PackageManager.GET_PERMISSIONS | 
                                      PackageManager.GET_PROVIDERS)