测试图像在这里： http://images.plurk.com/tn_4134189_bf54fe8e270ce41240d534b5133884ee.gif

我试着在互联网上发现了几个解决方案，但目前还没有可行的解决方案。

I've tried several solutions found on the internet but there is no working solution.

我用下面的代码片段code：

I'm using the following snippet code:

Url imageUrl = new Url("https://m.xsw88.com/allimgs/daicuo/20230912/6244.png.gif");
Bitmap image = BitmapFactory.decodeStream(imageUrl.openStream());

始终得到这个日志：

Always getting this log:

DEBUG/skia(1441): --- decoder->decode returned false

任何帮助吗？ 谢谢你。

Any help? Thanks.

编辑：

这些图像没有被取消codeD也不能在的WebView 显示。如果开放，但可以看到一个浏览器。

Those images failed to be decoded are also can not be shown on a WebView. But can see if open in a Browser.

推荐答案

试试这个作为临时解决方法：

Try this as a temporary workaround:

首先添加下面的类：

  public static class PlurkInputStream extends FilterInputStream {

    protected PlurkInputStream(InputStream in) {
        super(in);
    }

    @Override
    public int read(byte[] buffer, int offset, int count)
        throws IOException {
        int ret = super.read(buffer, offset, count);
        for ( int i = 2; i < buffer.length; i++ ) {
            if ( buffer[i - 2] == 0x2c && buffer[i - 1] == 0x05
                && buffer[i] == 0 ) {
                buffer[i - 1] = 0;
            }
        }
        return ret;
    }

}

然后用PlurkInputStream包住原始数据流：

Then wrap your original stream with PlurkInputStream:

Bitmap bitmap = BitmapFactory.decodeStream(new PlurkInputStream(originalInputStream));

让我知道，如果这可以帮助你。

Let me know if this helps you.

编辑：

对不起，请尝试以下版本而不是：

Sorry please try the following version instead:

        for ( int i = 6; i < buffer.length - 4; i++ ) {
            if ( buffer[i] == 0x2c ) {
                if ( buffer[i + 2] == 0 && buffer[i + 1] > 0
                    && buffer[i + 1] <= 48 ) {
                    buffer[i + 1] = 0;
                }
                if ( buffer[i + 4] == 0 && buffer[i + 3] > 0
                    && buffer[i + 3] <= 48 ) {
                    buffer[i + 3] = 0;
                }
            }
        }

请注意，这不是有效的code，也没有这是一个充满/正确的解决方案。它适用于大多数的情况下，但不是全部。

Note that this is not efficient code nor is this a full/correct solution. It will work for most cases, but not all.