I'd like to get the name of the current Activity to be sent along in the URI of an HttpRequest. Is there a way to do this without referring specifically to the Activity?

我知道我可以做 myActivity.class.toString（）但是这仅仅是一个低效率的硬编码myActivity的方式，因为我做的静态引用我的活动。有没有做到这一点使用像'这个'（这顺便说一句实际上并没有在这里工作，因为它返回比期望的更多信息）一个更普遍的方式。

I know I can do myActivity.class.toString() but this is just a less efficient way of hard coding "myActivity" since I'm making a static reference to my Activity. Is there a more general way to do this using something like 'this' (which btw doesn't actually work here because it returns more information than what's desired).

推荐答案

使用 this.getClass（）。getSimpleName（）获得活动的名称。

从评论，如果您在上下文中的 OnClickListener （或其他内部类），手动指定类：

From the comments, if you're in the context of an OnClickListener (or other inner class), specify the class manually:

MainActivity.class.getSimpleName（）