我写在那里我处理4活动的应用程序，假设A，B，C和; D.活动A调用B，B调用C，C调用D.在每一个活动，我有一个叫做家的按钮按钮。当用户在任何的B点击home键，C，D活动，应用程序应该回到A活性屏？

如何模拟在这种情况下，家按钮？

  button.setOnClickListener（新View.OnClickListener（）{
    公共无效的onClick（视图v）{
        startActivity（新意图（贵方寄去化妆品，的A.class））;
    }
}）;
 

声明一个在你的清单与安卓launchMode =singleTask。这样，当你调用 startActivity（）从其他activies，而A已经在运行，它只是把它的前面。否则，它会启动一个新的实例。

I am writing a application where I am dealing with 4 activities, let's say A, B, C & D. Activity A invokes B, B invokes C, C invokes D. On each of the activity, I have a button called "home" button. When user clicks on home button in any of the B, C, D activities, application should go back to A activity screen ?

How to simulate "home" button in this case ?

button.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {
        startActivity(new Intent(D.this, A.class));
    }
});

Declare A in your manifest with the android:launchMode="singleTask". This way, when you call startActivity() from your other activies, and A is already running, it will just bring it to the front. Otherwise it'll launch a new instance.