得到一个地形设置内部的瓦片的左上位置瓦片、地形、位置

2023-09-11 23:24:21 作者:你別跑?

我有一个地形设置(全其它小图像的图像)。我想获得那些所谓的砖,所以我可以用它做什么小图像之一。我知道每瓦(他们都是一样大小)的大小。 我有两个等式:

  X =(I%tiles_hor)* tile_h
Y =(I%tiles_ver)* tile_w

X =(ⅰ%tiles_hor)* tile_w
Y =(I / tiles_hor)* tile_w
 

其中的我指的瓷砖我想要得到的指数; tiles_hor 是瓦水平的数量; tiles_ver 瓷砖是垂直的数量; tile_w 和 tile_h 的宽度和每瓦的地形设置,分别为内部高度;

瓷砖依次接收它们的索引,这样的:

  01 02 03 04 05
06 07 08 09 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25
 

所以每对位的它是地形设置内部的瓦片的索引。 比方说,我想要得到的04瓦(假设瓷砖各有一个32×32大小): 与第一方程:

X =(4%5)* 32 = 128。所以这是x位置内的图像是128 Y =(4%5)* 32 = 0,所以这是y中的图像内是0;

与第二式: X =(4%5)* 32 = 128。所以这是x位置内的图像是128 Y =(4/5)* 32 = 0这里的是0,因为我们是第一圆第一八佰伴pression为最接近的次设备号(我不知道是不是我的前pression是正确的。请纠正我,如果它不是)。

如图.抛物线y ax2 bx 3经过点A.与x轴负半轴交于点B.与y轴交于点C.且OC 3OB. 1 求抛物线的解析式, 2 点D在y轴上.且 BDO BAC.求点D的坐标, 3 点M在抛物线上

请注意,我们正在考虑一个完美的正方形地形设置(在这种情况下,5×5)

我的问题是: 第二种适用于大多数情况下。第一站时,有没有完美的正方形地形设置的,并具有很高的高空作业。 所以我在做什么错呢?

另外,如何可以是让出一个非常重要的价值(tiles_ver和tile_h)可能是正确的一个公式?我在想什么呢?

解决方案

  X =((I  -  1)%tiles_hor)* tile_w
Y =((I  -  1)/ tiles_hor)* tile_h
 

I have a tileset(a image full of other small images). And I wanna get one of those little images called tile so I can do something with it. I know the size of each tile(they're all the same size). I have two equations:

x = (i % tiles_hor) * tile_h
y = (i % tiles_ver) * tile_w

x = (i % tiles_hor) * tile_w
y =  (i / tiles_hor) * tile_w

where i means the index of the tile i wanna get; tiles_hor is the number of tiles horizontally; tiles_ver is the number of tiles vertically; tile_w and tile_h is the width and height of each tile inside the tileset, respectively;

The tiles receive their index sequentially, like this:

01 02 03 04 05 
06 07 08 09 10
11 12 13 14 15
16 17 18 19 20
21 22 23 24 25

So each pair of digit it's the index of a tile inside the tileset. Let's say I wanna get the tile 04(assuming the tiles have a 32x32 size each): with the first equation:

x = (4 % 5) * 32 = 128. So it's x position inside the image is 128 y = (4 % 5) * 32 = 0. So it's y inside the image is 0;

with the second equation: x = (4 % 5) * 32 = 128. So it's x position inside the image is 128 y = (4 / 5) * 32 = 0. Here's is 0, cause we're first rounding the first expression for the closest minor number(i don't know if my expression is right. Please correct me if it's not).

Note that we're considering a perfect square tileset (in this case 5x5)

My question is: The second works for most cases. The first stop working when there's no perfect squares tileset's and with a high height. So what am I doing wrong there?

Also, how can be a equation that is letting out a really important value (tiles_ver and tile_h) can be right? What am I missing there?

解决方案

x = ((i - 1) % tiles_hor) * tile_w
y = ((i - 1) / tiles_hor) * tile_h