绘制,其中顶点之间的距离对应的边权重的曲线图曲线图、权重、顶点、距离

2023-09-11 04:57:26 作者:指尖滑过的年华﹌

有一个算法,给了我在图中坐标的顶点,当我给他一个加权图和顶点点之间的边的权到距离顶点之间 ?

是这样的:

 公共_ArrayOfCoordinatesForVertices_ ** super_hyper_algorithm **(weighted_graph){
     返回_foo_;
}
 

解决方案

这是一般不可能的:想象一下,有3个节点N1,N2和N3图

等边三角形中点到各顶点的距离怎么求

现在考虑下面的距离:

  N1-N2:4
N1-N3:1
N2-N3:1
 

(这违反了三角不等式的推广)。

Is there an algorithm that gives me coordinates of vertices in a graph, when I give him a weighted graph and the edge weights between vertices points to the distance between vertices?

Something like:

public _ArrayOfCoordinatesForVertices_ **super_hyper_algorithm**(weighted_graph){  
     return _foo_;  
}

解决方案

This is in general not possible: Imagine a graph with 3 nodes n1, n2, and n3.

now consider the following distances:

n1-n2: 4
n1-n3: 1
n2-n3: 1

(This violates the triangle inquality).