我在哪里可以找到 LogLog算法的有效实施？试图通过我自己，但我的草案实施收益奇怪的结果来实现它。

Where can I find a valid implementation of LogLog algorithm? Have tried to implement it by myself but my draft implementation yields strange results.

这里是：

function LogLog(max_error, max_count)
{
    function log2(x)
    {
         return Math.log(x) / Math.LN2;
    }

    var m = 1.30 / max_error;
    var k = Math.ceil(log2(m * m));
    m = Math.pow(2, k);

    var k_comp = 32 - k;

    var l = log2(log2(max_count / m));
    if (isNaN(l)) l = 1; else l = Math.ceil(l);
    var l_mask = ((1 << l) - 1) >>> 0;

    var M = [];
    for (var i = 0; i < m; ++i) M[i] = 0;

    function count(hash)
    {
          if (hash !== undefined)
          {
                var j = hash >>> k_comp;

                var rank = 0;
                for (var i = 0; i < k_comp; ++i)
                {
                     if ((hash >>> i) & 1)
                     {
                          rank = i + 1;
                          break;
                     }
                }

                M[j] = Math.max(M[j], rank & l_mask);
          }
          else
          {
                var c = 0;
                for (var i = 0; i < m; ++i) c += M[i];
                return 0.79402 * m * Math.pow(2, c / m);
          }
    }

    return {count: count};
}

function fnv1a(text)
{
     var hash = 2166136261;
     for (var i = 0; i < text.length; ++i)
     {
          hash ^= text.charCodeAt(i);
          hash += (hash << 1) + (hash << 4) + (hash << 7) +
            (hash << 8) + (hash << 24);
     }
    return hash >>> 0;
}

var words = ['aardvark', 'abyssinian', ... ,'zoology']; // about 2 300 words

var log_log = LogLog(0.01, 100000);
for (var i = 0; i < words.length; ++i) log_log.count(fnv1a(words[i]));
alert(log_log.count());

有关不明原因的实现是 max_error 参数非常敏感，这是主要的因素，决定结果的大小。我敢肯定，有一些愚蠢的错误：）

For unknown reason implementation is very sensitive to max_error parameter, it is the main factor that determines the magnitude of the result. I'm sure, there is some stupid mistake :)

更新：这个问题解决了算法的更新版本 。我将在稍后发布实施。

UPDATE: This problem is solved in the newer version of algorithm. I will post its implementation later.

推荐答案

这里它是基于算法的更新版本在新纸：

Here it is the updated version of the algorithm based on the newer paper:

var pow_2_32 = 0xFFFFFFFF + 1;

function HyperLogLog(std_error)
{
     function log2(x)
     {
          return Math.log(x) / Math.LN2;
     }

     function rank(hash, max)
     {
          var r = 1;
          while ((hash & 1) == 0 && r <= max) { ++r; hash >>>= 1; }
          return r;
     }

     var m = 1.04 / std_error;
     var k = Math.ceil(log2(m * m)), k_comp = 32 - k;
     m = Math.pow(2, k);

     var alpha_m = m == 16 ? 0.673
          : m == 32 ? 0.697
          : m == 64 ? 0.709
          : 0.7213 / (1 + 1.079 / m);

     var M = []; for (var i = 0; i < m; ++i) M[i] = 0;

     function count(hash)
     {
          if (hash !== undefined)
          {
                var j = hash >>> k_comp;
                M[j] = Math.max(M[j], rank(hash, k_comp));
          }
          else
          {
                var c = 0.0;
                for (var i = 0; i < m; ++i) c += 1 / Math.pow(2, M[i]);
                var E = alpha_m * m * m / c;

                // -- make corrections

                if (E <= 5/2 * m)
                {
                     var V = 0;
                     for (var i = 0; i < m; ++i) if (M[i] == 0) ++V;
                     if (V > 0) E = m * Math.log(m / V);
                }
                else if (E > 1/30 * pow_2_32)
                     E = -pow_2_32 * Math.log(1 - E / pow_2_32);

                // --

                return E;
          }
    }

    return {count: count};
}

function fnv1a(text)
{
     var hash = 2166136261;
     for (var i = 0; i < text.length; ++i)
     {
          hash ^= text.charCodeAt(i);
          hash += (hash << 1) + (hash << 4) + (hash << 7) +
            (hash << 8) + (hash << 24);
     }
     return hash >>> 0;
}

var words = ['aardvark', 'abyssinian', ..., 'zoology']; // 2336 words

var seed = Math.floor(Math.random() * pow_2_32); // make more fun

var log_log = HyperLogLog(0.065);
for (var i = 0; i < words.length; ++i) log_log.count(fnv1a(words[i]) ^ seed);
var count = log_log.count();
alert(count + ', error ' +
    (count - words.length) / (words.length / 100.0) + '%');