我试图让JSON形成其他领域，我的code是如下：

I'm trying to get json form other domain, my code is as below:

var token = '';
function getData(){
  console.log("get data suc");
  for (var i=0; i < urls.length; i++){
     var code = 'http://example.com/api/'+ urls[i];
     $.ajax({
       async: false,
       url: code,
       type: 'GET',
       dataType: 'jsonp',
       success: function(data) { showData(data); },
       error: function() { console.log('ajax Failed!'); },
       beforeSend: setHeader,
     });
  }
}
function showData(data){
  $("<tr></tr>").append("<td>" + data + "</td>")
    .appendTo("#results");
  console.log(data);
}
function setHeader(xhr) {
  xhr.setRequestHeader('Authorization', token);
}

这个结果应该显示为秩序的关键，我从阵列的网址给了。 例如：网址= [1,2,3,4]→应该得到[一，二，三，四] 但我总是得到错误的顺序（例如：二，一，三，四]或[三，四，二，一]）！ 发生了什么？ 那是异步：假没有工作？为什么？

This result should be display as order the key I gave from array urls. ex: urls = [1,2,3,4]→should get [one,two,three,four] but I always get the wrong order!(ex: [two,one,three,four] or [three,four,two,one]) What happened? Is that "async: false" didn't work? And why?

推荐答案

您使用的是 JSONP 的要求，不支持异步：假。

You are using a jsonp request which does not support async:false.

在默认情况下，所有的请求都异步发送（即此设置为   默认值是true）。如果您需要同步请求，设置这个选项   假。跨域请求和数据类型：JSONP请求不   支持同步操作。请注意，同步请求可能   暂时锁定浏览器，禁用而请求的任何行动   是活性

By default, all requests are sent asynchronously (i.e. this is set to true by default). If you need synchronous requests, set this option to false. Cross-domain requests and dataType: "jsonp" requests do not support synchronous operation. Note that synchronous requests may temporarily lock the browser, disabling any actions while the request is active.

因此​​，尝试

function getData() {
    function request(urls, i) {
        var code = 'http://example.com/api/' + urls[i];
        $.ajax({
            async: false,
            url: code,
            type: 'GET',
            dataType: 'jsonp',
            success: function (data) {
                showData(data);
            },
            error: function () {
                console.log('ajax Failed!');
            },
            beforeSend: setHeader,
        }).always(function () {
            i++;
            if (i < urls.length) {
                request(urls, i);
            }
        });
    }
    console.log("get data suc");
    request(urls, 0);
}