我有以下的code在PHP中，允许用户选择从下拉列表中的名称，然后通过该名称作为一个字符串交给一个JavaScript函数：

I have the following code in PHP that allows the user to select a name from a drop-down, then pass that name as a string over to a JavaScript function:

<?php
                include('./db.php');
                $PM = mysqli_query($con, "SELECT DISTINCT PMName FROM report WHERE PMname <> '' ORDER BY PMName ASC");
                ?>
                <select class="navbar-inverse" placeholder="PM Name" name="PMName" onchange="showUser(this.value)">
                <?php
                while ($row = mysqli_fetch_row($PM)) {
                $selected = array_key_exists('PMName', $_POST) && $_POST['PMName'] == $row[0] ? ' selected' : '';
                printf(" <option value='%s' %s>%s</option>\n", $row[0], $selected, $row[0]);
                }
                ?>

JavaScript函数然后读取字符串：

The JavaScript function then reads the string:

function showUser(str) {
  if (str !==".PM") {
    if (str=="") {
      document.getElementById("txtHint").innerHTML="";
      return;
    } 
  }
  $("#txtHint").load( "getuser.php?q="+str );
    console.log(str);
}

和应该放置的输出 getuser.php？Q =约翰％李四 到 txtHint DIV。

and is supposed to place the output of getuser.php?q=John%Doe into the txtHint DIV.

在 STR 的价值似乎并没有完全传递到 $（＃txtHint）的负载（getuser.php Q =？+ STR）; 的code线

the str value does not APPEAR to be fully passing into the $("#txtHint").load( "getuser.php?q="+str ); line of code.

当我看着我的控制台，我看到下面的一次JavaScript函数火灾：

When I look at my console, I see the following once the JavaScript function fires:

HR finished loading: GET "http://localhost/getuser.php?q=John"
John Doe

如果我改变code阅读只是 $（＃txtHint）的负载（getuser.php Q =？）; ，（不通过了 STR 变量），它工作正常，并加载getuser.php页放入DIV，（当然，没有名字，我不回来任何信息，但它的工作原理......）

If I change the code to read just $("#txtHint").load( "getuser.php?q=");, (without passing the str variable,) it works fine and loads the getuser.php page into the DIV, (of course, without a name I don't get back any info, but it works...)

我在做什么错在这里？如果的console.log（STR）正在输出李四，那么很明显，整个字符串李四，所以为什么我的控制台输出？Q =约翰·？并造成getuser.php不加载到DIV？

What am I doing wrong here? If the console.log(str) is outputting John Doe, then obviously the entire string is John Doe, so why is my console outputting ?q=John? and causing getuser.php not to load into the DIV?

我很困惑在这里...

I'm very confused here....

推荐答案

您需要连接code的字符串，如果你想将它作为一个查询变量发送：

You need to encode your string if you want to send it as a query variable:

$("#txtHint").load( "getuser.php?q="+encodeURIComponent(str));