我想获得的话preSS一个Ajax请求的结果,但我在JavaScript中的一个警告框,让'0',所以形式如下:
I am trying to get the results of an ajax request in wordpress, but I am getting result of '0' in an alert box of javascript, so the form looks like this:
<form class="form" id="ajax-contact-form" action="#">
<input type="text" name="name" id="name" placeholder="Name" required="">
<button type="submit" class="btn">Submit</button>
</form>
中的JavaScript看起来是这样的:
The javascript looks like this:
$('#ajax-contact-form').submit(function(e){
$.ajax({
data: {action: 'contact_form'},
type: 'post',
url: ajaxurl,
success: function(data) {
alert(data); // This prints '0', I want this to print whatever name the user inputs in the form.
}
});
})
和PHP的:
add_action('wp_ajax_contact_form', 'contact_form');
add_action('wp_ajax_nopriv_contact_form', 'contact_form');
function contact_form()
{
echo $_POST['name'];
}
有谁知道,如果code以上是正确的,我也尝试$ _REQUEST ['名称'],它不工作。
Does anyone know if the code above is correct, I have also tried $_REQUEST['name'] and it doesnt work.
感谢洙多,
尝试是这样的:
$('#ajax-contact-form').submit(function(e){
var name = $("#name").val();
$.ajax({
data: {action: 'contact_form', name:name},
type: 'post',
url: ajaxurl,
success: function(data) {
alert(data); //should print out the name since you sent it along
}
});
});