我要建一个应用程序使用ActionScript 3.0在我的Flash Builder中。这是一个后续问题this问题，它的工作原理，但是当我拍摄照片，拍摄的图像旋转到左边。我怎么能检查哪些方式，用户拿着手机？然后呢code做我使用到它的相应位置，将图像旋转？

I'm building an App with actionscript 3.0 in my Flash builder. This is a followup question to this question, It works but when I take the picture, the image comes out rotated to the left. how can I check which way the user is holding the phone? and then what code do I use to rotate the image to it's corresponding place?

在先进的感谢！

编辑： 我使用这个code旋转图像，但它似乎只旋转图像显示没有图像文件，任何想法？

I'm using this code to rotate the image, but it seems to only rotate the image being displayed not the image file, any ideas?

var mat:Matrix = new Matrix();
mat.translate(-W/2, -H/2);
mat.rotate(Math.PI/2);
mat.translate(+W/2, +H/2);
mat.concat(myObj.transform.matrix);
myObj.transform.matrix = mat;

〜MYY

推荐答案

您可以使用 Stage.deviceOrientation 或 Stage.orientation *，以确定哪种方式轮手机。

You can use Stage.deviceOrientation or Stage.orientation* to determine which way round the phone is.

*不知道这一件作品在iOS

*not sure if this one works on iOS

时它的BitmapData结果本身要旋转（即创建一个新的BitmapData旋转的图像），或者只需旋转显示列表中的一个位图？

Is it the BitmapData result itself that you want to rotate (ie create a new BitmapData with rotated image) or just rotate a Bitmap on the display list?

编辑：

好吧，继承人一些code旋转BitmapData对象：

Ok, heres some code to rotate a BitmapData object:

function rotateBitmapData(angle:int, source:BitmapData):BitmapData
{
    var newWidth:int = source.rect.width;
    var newHeight:int = source.rect.height;
    if (angle==90 || angle==270)
    {
        newWidth = source.rect.height;
        newHeight = source.rect.width;
    }
    var newBmd:BitmapData = new BitmapData(newWidth, newHeight, source.transparent);
    var tx:Number = 0;
    var ty:Number = 0;
    if (angle==90 || angle==180)
    {
        tx = newWidth;
}
    if (angle==180 || angle==270)
    {
        ty = newHeight;
    }
    var matrix:Matrix = new Matrix();
    matrix.createBox(1, 1, Math.PI*angle/180, tx, ty);
    newBmd.draw(source, matrix);
    return newBmd;
}

角度应该是0,90,180或270这将返回指定角度旋转的新的BitmapData对象。

angle should be 0,90,180 or 270. It will return a new BitmapData object rotated by specified angle.