我有一个数组猫，狗，鹦鹉

和希望通过索引中删除该项目。

目前，我有

 函数removeit（myindex）{
    动物[myindex] = animals.pop（）
}
 

解决方案

您想拼接

http://help.adobe.com/en_US/FlashPlatform/reference/actionscript/3/Array.html#splice%28%29

Array.splice（起点，删除数）;

  VAR newArray：阵列= myArray.splice（2,1）; //这将删除一切是在索引2并返回一个新的数组。
 

更改功能

 函数removeit（myindex）{
    animals.splice（myindex，1）;
}
 

I have an array 'cat', 'dog', 'budgie'

and want to remove the item by index.

At the moment I have

function removeit(myindex) {
    animals[myindex] = animals.pop()
}

You want splice

http://help.adobe.com/en_US/FlashPlatform/reference/actionscript/3/Array.html#splice%28%29

Array.splice(starting point, remove count);

 var newArray:Array = myArray.splice(2, 1); //this removes whatever is at index 2 and returns it in a new array.

Change your function to

function removeit(myindex) {
    animals.splice(myindex, 1);
}