我使用YouTube AS3播放器API来加载视频在Flash项目。 我正在载入播放器SWF的时候得到这个真的很烦错误:
引发SecurityError:错误#2047:安全沙箱冲突:父:http://www.degoudenglimlach.be/main.swf无法访问http://www.youtube.com/ [ [进口] / s.ytimg.com/yt/swf/watch_as3-vflbgr4dW.swf。
我尝试加载的SWF之前添加以下到我的code,但它并没有任何区别:
的Security.allowDomain(*);
的Security.allowDomain(www.youtube.com);
的Security.allowDomain(youtube.com);
的Security.allowDomain(s.ytimg.com);
的Security.allowDomain(i.ytimg.com);
任何帮助将是巨大的。
下面是我的完整的包装类:
包be.zap.media
{
进口flash.display.Loader;
进口flash.display.Sprite;
进口对象类型:flash.events.Event;
进口flash.net.URLRequest;
进口类flash.system.Security;
进口flash.system.System;
/ **
* ...
* @author日元Resmann
* /
公共类ZapYoutubeVideo扩展Sprite
{
私人VAR ytPlayer:对象;
私人VAR LDR:装载机
私有静态常量YOUTUBE_EMBEDDED_PLAYER_URL:字符串=http://www.youtube.com/v/VIDEO_ID?version=3;
公共静态常量PLAYER_READY:字符串=playerReady;
公共静态常量QUALITY_SMALL:字符串=小;
公共静态常量QUALITY_MEDIUM:字符串=中等;
公共静态常量QUALITY_LARGE:字符串=大;
公共静态常量QUALITY_HD720:字符串=HD720;
公共静态常量QUALITY_HD1080:字符串=HD1080;
公共静态常量QUALITY_HIGHRES:字符串=HIGHRES;
公共静态常量QUALITY_DEFAULT:字符串=默认;
公共职能ZapYoutubeVideo()
{
的Security.allowDomain(*);
的Security.allowDomain(www.youtube.com);
的Security.allowDomain(youtube.com);
的Security.allowDomain(s.ytimg.com);
的Security.allowDomain(i.ytimg.com);
LDR =新的Loader();
ldr.contentLoaderInfo.addEventListener(Event.INIT,handleInitPlayer);
的addEventListener(Event.REMOVED_FROM_STAGE,handleRemovedFromStage);
}
公共职能initPlayer(vidId:字符串)
{
变种网址:字符串= YOUTUBE_EMBEDDED_PLAYER_URL.split(VIDEO_ID)加入(vidId)。
ldr.load(新的URLRequest(URL));
}
私有函数handleInitPlayer(五:事件):无效
{
的addChild(LDR);
ldr.contentLoaderInfo.removeEventListener(Event.INIT,handleInitPlayer);
ldr.content.addEventListener(onReady,handlePlayerReady);
ldr.content.addEventListener(onError的,handlePlayerError);
ldr.content.addEventListener(onStateChange,handlePlayerStageChange);
ldr.content.addEventListener(onPlaybackQualityChange,handlePlayerQualityChange);
}
私有函数handlePlayerReady(五:事件):无效
{
ytPlayer = ldr.content;
则dispatchEvent(新的事件(PLAYER_READY));
}
公共职能queueVideoById(VIDEOID:字符串,质量:字符串= QUALITY_DEFAULT):无效
{
ytPlayer.cueVideoById(VIDEOID,0,质量);
}
公共职能loadVideoById(VIDEOID:字符串,质量:字符串= QUALITY_DEFAULT):无效
{
ytPlayer.loadVideoById(VIDEOID,0,质量);
}
公共职能queueVideoByUrl(网址:字符串,质量:字符串= QUALITY_DEFAULT):无效
{
ytPlayer.cueVideoByUrl(URL,0,质量);
}
公共职能loadVideoByUrl(网址:字符串,质量:字符串= QUALITY_DEFAULT):无效
{
ytPlayer.loadVideoByUrl(URL,0,质量);
}
公共职能的setSize(W:INT,H:INT):无效
{
ytPlayer.setSize(W,H);
}
私有函数handlePlayerError(五:事件):无效
{
}
私有函数handlePlayerStageChange(五:事件):无效
{
}
私有函数handlePlayerQualityChange(五:事件):无效
{
}
私有函数handleRemovedFromStage(五:事件):无效
{
removeEventListener(Event.REMOVED_FROM_STAGE,handleRemovedFromStage);
配置();
}
公共职能的Dispose():无效
{
ytPlayer.destroy();
如果(LDR){
如果(包含(LDR)){
removeChild之(LDR);
}
LDR = NULL;
}
}
/ **
*解析出YouTube视频ID的视频网址
* @参数的URL
* @返回字符串
* /
公共静态函数getIdFromURL(网址:字符串):字符串
{
VAR部分:数组= [];
如果(url.indexOf(手表?ν=)!= -1){
部分= url.split(看V =?);
}否则,如果(url.indexOf(手表/ V /)!= -1){
部分= url.split(手表/ V /);
}否则如果(url.indexOf(youtu.be/)!= - 1){
部分= url.split(youtu.be/);
}
返回字符串(地区[1])分裂(/)参加()。;
}
/ **
*获得视频的缩略图
* @参数字符串的YouTube视频ID
* @返回的URLRequest
* /
公共静态函数getThumbnail(VIDEOID:字符串)的URLRequest
{
返回新的URLRequest(http://img.youtube.com/vi/+ VIDEOID +/0.jpg);
}
}
}
解决方案
我不认为这是可能的,看的错误信息,你应该看到,他们主要是不得不面对的事实是,YouTube已经没有更新他们的跨域策略文件并没有指定元策略。这里是他们的策略文件:
<! - http://www.youtube.com/crossdomain.xml - >
<!DOCTYPE跨域政策
SYSTEMhttp://www.macromedia.com/xml/dtds/cross-domain-policy.dtd">
<交域政策>
<* youtube.com允许访问,从域= />
<允许存取来自域=s.ytimg.com/>
< /跨域策略>
他们需要增加这样一行:
<现场控制允许交叉域策略=所有/>
I'm using the Youtube AS3 Player API to load video's in a Flash Project. I get this really annoying Error when loading the Player swf:
SecurityError: Error #2047: Security sandbox violation: parent: http://www.degoudenglimlach.be/main.swf cannot access http://www.youtube.com/[[IMPORT]]/s.ytimg.com/yt/swf/watch_as3-vflbgr4dW.swf.
I tried adding the following to my code before loading the swf but it doesn't make any difference:
Security.allowDomain("*");
Security.allowDomain("www.youtube.com");
Security.allowDomain("youtube.com");
Security.allowDomain("s.ytimg.com");
Security.allowDomain("i.ytimg.com");
Any Help would be great.
Here's my full Wrapper class:
package be.zap.media
{
import flash.display.Loader;
import flash.display.Sprite;
import flash.events.Event;
import flash.net.URLRequest;
import flash.system.Security;
import flash.system.System;
/**
* ...
* @author Yens Resmann
*/
public class ZapYoutubeVideo extends Sprite
{
private var ytPlayer : Object;
private var ldr : Loader
private static const YOUTUBE_EMBEDDED_PLAYER_URL : String = "http://www.youtube.com/v/VIDEO_ID?version=3";
public static const PLAYER_READY : String = "playerReady";
public static const QUALITY_SMALL : String = "small";
public static const QUALITY_MEDIUM : String = "medium";
public static const QUALITY_LARGE : String = "large";
public static const QUALITY_HD720 : String = "hd720";
public static const QUALITY_HD1080 : String = "hd1080";
public static const QUALITY_HIGHRES : String = "highres";
public static const QUALITY_DEFAULT : String = "default";
public function ZapYoutubeVideo()
{
Security.allowDomain("*");
Security.allowDomain("www.youtube.com");
Security.allowDomain("youtube.com");
Security.allowDomain("s.ytimg.com");
Security.allowDomain("i.ytimg.com");
ldr = new Loader();
ldr.contentLoaderInfo.addEventListener(Event.INIT, handleInitPlayer);
addEventListener(Event.REMOVED_FROM_STAGE, handleRemovedFromStage);
}
public function initPlayer(vidId : String)
{
var url : String = YOUTUBE_EMBEDDED_PLAYER_URL.split("VIDEO_ID").join(vidId);
ldr.load(new URLRequest(url));
}
private function handleInitPlayer(e:Event):void
{
addChild(ldr);
ldr.contentLoaderInfo.removeEventListener(Event.INIT, handleInitPlayer);
ldr.content.addEventListener("onReady", handlePlayerReady);
ldr.content.addEventListener("onError", handlePlayerError);
ldr.content.addEventListener("onStateChange", handlePlayerStageChange);
ldr.content.addEventListener("onPlaybackQualityChange", handlePlayerQualityChange);
}
private function handlePlayerReady(e:Event):void
{
ytPlayer = ldr.content;
dispatchEvent(new Event(PLAYER_READY));
}
public function queueVideoById(videoID : String, quality : String = QUALITY_DEFAULT):void
{
ytPlayer.cueVideoById(videoID, 0, quality);
}
public function loadVideoById(videoID : String, quality : String = QUALITY_DEFAULT):void
{
ytPlayer.loadVideoById(videoID, 0, quality);
}
public function queueVideoByUrl(url : String, quality : String = QUALITY_DEFAULT):void
{
ytPlayer.cueVideoByUrl(url, 0, quality);
}
public function loadVideoByUrl(url : String, quality : String = QUALITY_DEFAULT):void
{
ytPlayer.loadVideoByUrl(url, 0, quality);
}
public function setSize(w:int, h:int):void
{
ytPlayer.setSize(w, h);
}
private function handlePlayerError(e:Event):void
{
}
private function handlePlayerStageChange(e:Event):void
{
}
private function handlePlayerQualityChange(e:Event):void
{
}
private function handleRemovedFromStage(e:Event):void
{
removeEventListener(Event.REMOVED_FROM_STAGE, handleRemovedFromStage);
dispose();
}
public function dispose():void
{
ytPlayer.destroy();
if (ldr) {
if (contains(ldr)) {
removeChild(ldr);
}
ldr = null;
}
}
/**
* parse out the Youtube Video ID from the video URL
* @param url
* @return String
*/
public static function getIdFromURL(url:String):String
{
var parts : Array = [];
if (url.indexOf("watch?v=") != -1) {
parts = url.split("watch?v=");
} else if (url.indexOf("watch/v/") != -1) {
parts = url.split("watch/v/");
} else if (url.indexOf("youtu.be/") != -1) {
parts = url.split("youtu.be/");
}
return String(parts[1]).split("/").join("");
}
/**
* get the thumbnail of the video
* @param String youtube Video ID
* @return URLRequest
*/
public static function getThumbnail(videoId : String):URLRequest
{
return new URLRequest("http://img.youtube.com/vi/" + videoId + "/0.jpg");
}
}
}
解决方案
I don't think it's possible , look at the error messages and you should see that they mainly have to deal with the fact that YouTube hasn't updated their crossdomain policy file and doesn't specify a meta policy. here's their policy file:
<!-- http://www.youtube.com/crossdomain.xml -->
<!DOCTYPE cross-domain-policy
SYSTEM "http://www.macromedia.com/xml/dtds/cross-domain-policy.dtd">
<cross-domain-policy>
<allow-access-from domain="*.youtube.com" />
<allow-access-from domain="s.ytimg.com" />
</cross-domain-policy>
They need to add a line like this:
<site-control permitted-cross-domain-policies="all"/>