所以我有一个3D实时更新的图形！这只能说明一点的时间，所以我可以很容易地跟踪点的运动！但现在的问题是：

So I have a 3d live-updating graph! it only shows one point at a time so I can easily track the motion of the point! But here is the problem:

无论我似乎做，点始终放在图表和轴变化的刻度线的中心，为了做到这一点。这使我的生活非常困难，因为我看不到的点的运动。这是我的code：

No matter what I seem to do, the point is always placed in the center of the graph and the tick marks on the axis change in order to do that. This makes my life very difficult because I don't see the motion on the point. Here is my code:

from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
from pylab import *
import time
import pandas as pd
import pickle
def pickleLoad(pickleFile):
    pkl_file = open(pickleFile, 'rb')
    data = pickle.load(pkl_file)
    pkl_file.close()
    return data
data = pickleLoad('/Users/ryansaxe/Desktop/kaggle_parkinsons/accelerometry/LILY_dataframe')
data = data.reset_index(drop=True)
df = data.ix[0:,['x.mean','y.mean','z.mean','time']]
ion()
fig = figure()
ax = fig.add_subplot(111, projection='3d')
count = 0
plotting = True
labels = range(-10,11)
ax.set_xlabel('X Label')
ax.set_ylabel('Y Label')
ax.set_zlabel('Z Label')
ax.set_yticklabels(labels)
ax.set_xticklabels(labels)
ax.set_zticklabels(labels)
lin = None
while plotting:
    df2 = df.ix[count]
    count += 1
    xs = df2['x.mean']
    ys = df2['y.mean']
    zs = df2['z.mean']
    t = df2['time']
    ax.set_title(t)
    if lin is not None:
        lin.remove()
    lin = ax.scatter(xs, ys, zs)

    draw()
    pause(0.01)
    if count > 100:
        plotting = False
ioff()
show()

这里是数据的示例：

here is an example of the data:

     x.mean    y.mean    z.mean                 time
0 -1.982905  3.395062  8.558263  2012-01-18 14:00:03
1  0.025276 -0.399172  7.404849  2012-01-18 14:00:04
2 -0.156906 -8.875595  1.925565  2012-01-18 14:00:05
3  2.643088 -8.307801  2.382624  2012-01-18 14:00:06
4  3.562265 -7.875230  2.312898  2012-01-18 14:00:07
5  4.441432 -7.907592  2.851774  2012-01-18 14:00:08
6  4.124187 -7.854146  2.727229  2012-01-18 14:00:09
7  4.199698 -8.135596  2.677706  2012-01-18 14:00:10
8  4.407856 -8.133449  2.214902  2012-01-18 14:00:11
9  4.096238 -8.453822  1.359692  2012-01-18 14:00:12

所以，我能做些什么来让这个刻度线是固定的所以点移动，而不是刻度线的变化？

推荐答案

这是 Axes3D 对象（你的斧变量）有以下方法： set_xlim ， set_ylim 和 set_zlim 。你可以用它们来修复您的轴的限制。

An Axes3D object (your ax variable) has the following methods: set_xlim, set_ylim, and set_zlim. You could use these to fix the limits of your axes.

文件：

修改

使用 set_xlim 等，对我的作品。这是我的code：

Using set_xlim, etc, works for me. Here is my code:

#!python2

from mpl_toolkits.mplot3d import Axes3D
from pylab import *

data = [
    [-1.982905,  3.395062,  8.558263,  '2012-01-18 14:00:03'],
    [ 0.025276, -0.399172,  7.404849,  '2012-01-18 14:00:04'],
    [-0.156906, -8.875595,  1.925565,  '2012-01-18 14:00:05'],
    [ 2.643088, -8.307801,  2.382624,  '2012-01-18 14:00:06'],
    [3.562265, -7.875230,  2.312898,  '2012-01-18 14:00:07'],
    [4.441432, -7.907592,  2.851774,  '2012-01-18 14:00:08'],
    [4.124187, -7.854146,  2.727229,  '2012-01-18 14:00:09'],
    [4.199698, -8.135596,  2.677706,  '2012-01-18 14:00:10'],
    [4.407856, -8.133449,  2.214902,  '2012-01-18 14:00:11'],
    [4.096238, -8.453822,  1.359692,  '2012-01-18 14:00:12'],
]

ion()
fig = figure()
ax = fig.add_subplot(111, projection='3d')
ax.set_xlabel('X Label')
ax.set_ylabel('Y Label')
ax.set_zlabel('Z Label')
ax.set_xlim((-10, 11))
ax.set_ylim((-10, 11))
ax.set_zlim((-10, 11))

lin = None
for x, y, z, t in data:
    ax.set_title(t)
    if lin is not None:
        lin.remove()
    lin = ax.scatter(x, y, z)
    draw()
    pause(0.1)

ioff()
show()

编辑2

您可以看看关闭轴自动缩放，这是默认。也许这是覆盖 set_lim 的方法。

You could have a look at switching off autoscaling of axes which is on by default. Maybe this is overriding the set_lim methods.

文件：