我要生成一个随机整数是：

在区间[最小，最大] 包括 的范围可以是[5,20]，[-29，-3]或[-13，13]（它可以在任何范围内，正或负或之间）的的code采用的是Android做工精细

我走到这一步，是这样的，但似乎不负范围的工作！

  1 +（INT）（的Math.random（）*（（最大值 - 最小值）+ 1））; 

解决方案

我是pretty确定要将

 敏+（INT）（的Math.random（）*（（最大值 - 最小值）+ 1））; 

不过，我要指出的范围[-3，-29]有它的最小和最大逆转。 （而且具有相同的[5,1 -13]作为通过Merlyn指出）。

如果你想只是把任意两个号码的范围，a和b然后使用code

 诠释最小= Math.min（A，B）;INT最大= Math.max（A，B）; 

这样，你将不必担心秩序。这甚至会为一个== b工作。

I want to generate a random Integer that is:

Inside the range [Min, Max] inclusive The range can be [5,20], [-29, -3] or [-13, 13] (It can be in any range, positive or negative or in between) The code is working fine in Android

What I got so far is this, but it seems not working with negative ranges !

1 + (int)(Math.random() * ((Max - Min) + 1));

解决方案

I'm pretty sure you want

Min+(int)(Math.random()*((Max-Min) + 1));

However, I should point out that the range [-3,-29] has its min and max reversed. (And the same with [5,-13] as was pointed out by Merlyn.)

If you want to just put in any two numbers for the range, a and b then use the code

int Min = Math.min(a,b);
int Max = Math.max(a,b);

That way you won't have to worry about the order. This will even work for a==b.