我正在构建一个通用 Web 服务，需要将所有查询参数抓取到一个字符串中以供以后解析.我该怎么做?

I am building a generic web service and need to grab all the query parameters into one string for later parsing. How can I do this?

推荐答案

您可以通过 @QueryParam("name") 访问单个参数或通过上下文访问所有参数:

You can access a single param via @QueryParam("name") or all of the params via the context:

@POST
public Response postSomething(@QueryParam("name") String name, @Context UriInfo uriInfo, String content) {
     MultivaluedMap<String, String> queryParams = uriInfo.getQueryParameters(); 
     String nameParam = queryParams.getFirst("name");
}

关键是 @Context jax-rs注解，可用于访问:

The key is the @Context jax-rs annotation, which can be used to access:

UriInfo、请求、HttpHeaders、安全上下文，提供者

UriInfo, Request, HttpHeaders, SecurityContext, Providers