基于此代码直接来自 plotly 的 tut 页面:

Based on this code directly from plotly's tut page:

https://plot.ly/python/dropdowns/

现在，如果我不仅要更改图表类型，还要更改数据源及其图表类型，该怎么办?是否可以?

Now, what if I want to change not just the chart type but rather the data source and its chart type? Is it possible?

我玩过这个设置:

data1 = go.Surface(z=df.values.tolist(), colorscale='Viridis')
data2 = go.Heatmap(z=df.values.tolist())

buttons=list([   
            dict(
                args=[data1],
                label='3D Surface',
                method='restyle'
            ),
            dict(
                args=[data2],
                label='Heatmap',
                method='restyle'
            )             
        ])

但是，图表显示了，但被覆盖了.当我点击下拉菜单中的任何项目时，图表完全消失了.

However, the graphs are shown, but overlayed. And when I click any item in the dropdown menu, the graph is completely gone.

推荐答案

我自己找到了一个解决方案，其实就是基于tut:

I've found a solution myself, that is actually based on the tut:

import plotly
import plotly.graph_objs as go 
from datetime import datetime
import pandas_datareader as web

df = web.DataReader("aapl", 'google',
                    datetime(2015, 1, 1),
                    datetime(2016, 7, 1))

trace_high = go.Bar(    x=df.index,
                        y=df.High,
                        name='High')

trace_low = go.Scatter(x=df.index,
                       y=df.Low,
                       name='Low',
                       line=dict(color='#F06A6A'))

data = [trace_high, trace_low]


updatemenus = list([
    dict(active=-1,
         buttons=list([   
            dict(label = 'High',
                 method = 'update',
                 args = [{'visible': [True, False]},
                         {'title': 'Yahoo High'}]),

            dict(label = 'Low',
                 method = 'update',
                 args = [{'visible': [False, True]},
                         {'title': 'Yahoo Low'}])
        ]),
    )
])

layout = dict(title='Yahoo', showlegend=False,
              updatemenus=updatemenus)

fig = dict(data=data, layout=layout)

plotly.offline.plot(fig, auto_open=False, show_link=False)