阅读一个Zip压缩文件内的文件，并把它的内容到Android中的String它的、并把、压缩文件、文件
这是我的第一个问题，虽然我已经使用的堆栈溢出这么多的技巧。但是，对于这种情况我还没有找到一个解决办法。
下面的情况：我有一个压缩文件，我想读一个特定的文件，并把它的内容到字符串变量，将返回并投入Android的一个TextView。我不希望要写入的文件到SD卡，我只是想执行内存操作。
例如，里面db.zip我有一个名为packed.txt文件，内容是堆栈权证。在我的方法返回的字符串显示83 116 97 99 107 32 195 161 32（...），这是UTF-8值的字符。我试过到目前为止converting'em一个人readble形式，但没有成功。尝试InputStreamReader的，但我不能作出正确的使用它。我的源 - code是如下。
进口的java.io.File;
进口java.io.FileInputStream中;
进口java.io.FileOutputStream中;
进口java.util.zip.ZipEntry中;
进口java.util.zip.ZipInputStream中;
进口android.util.Log;
/ **
*
* @author乔恩
* /
公共类DECOM preSS {
私人字符串_zipFile;
私人字符串_location;
公共DECOM preSS（字符串的压缩文件，字符串位置）{
_zipFile = zip文件;
_location =位置;
_dirChecker（）;
}
公共字符串解压缩（字符串desiredFile）{
字符串strUnzipped =;
尝试 {
的FileInputStream鳍=新的FileInputStream（_zipFile）;
ZipInputStream ZIN =新ZipInputStream（翅）;
ZipEntry的泽= NULL;
而（（泽= zin.getNextEntry（））！= NULL）{
Log.v（DECOM preSS的，解压缩+ ze.getName（））;
如果（ze.isDirectory（））{
_dirChecker（ze.getName（））;
} 其他 {
// FileOutputStream中FOUT =新的FileOutputStream（_location + ze.getName（））;
/ ****做以下****更改/
如果（ze.getName（）的toString（）。等于（desiredFile））{
字节[]字节=新字节[（INT）ze.getSize（）];
如果（zin.read（字节，0，bytes.length）== bytes.length）{
strUnzipped =新字符串（字节，UTF-8）;
}
其他 {
strUnzipped =读取错误......;
}
/ *** REMOVED
如果（ze.getName（）== desiredFile）{
对于（INT C = zin.read（）; C = -1;！C = zin.read（））{
strUnzipped + = C;
//fout.write(c）;
} * /
}
zin.closeEntry（）;
//fout.close（）;
}
}
zin.close（）;
}赶上（例外五）{
Log.e（DECOM preSS，解压，E）;
}
返回strUnzipped;
}
私人无效_dirChecker（字符串DIR）{
文件F =新的文件（_location +方向）;
如果（！f.isDirectory（））{
f.mkdirs（）;
}
}
}
解决方案
对不起，这个我最初发帖....正确的跑了过来，您的段落，说明你已经尝试过这一点。
您可以创建一个字符集的InputStreamReader的UTF-8，它会自动将输入数据转换成正确的字符给你。
，而（（泽= zin.getNextEntry（））！= NULL）{
Log.v（DECOM preSS的，解压缩+ ze.getName（））;
如果（ze.isDirectory（））{
_dirChecker（ze.getName（））;
} 其他 {
如果（ze.getName（）== desiredFile）{
字节[]字节=新字节[ze.getSize（）];
zin.read（字节，0，bytes.length）;
strUnzipped =新字符串（字节，UTF-8）;
/ *删除这个，因为它更容易刚才读的所有字节一次
InputStreamReader的ISR =新的InputStreamReader（ZIN，UTF-8）;
字符C = 0;
对于（字符C = isr.read（）; C = -1;！C = isr.read（））{
strUnzipped + = C;
}
* /
}
zin.closeEntry（）;
}
}
请尝试上面的，看看它是如何工作的。
this is my first question, although I've already used so many tips from Stack Overflow. But for this situation I haven't found a solution yet.
Here's the situation: I have a zipped file and I want to read a specific file and put its content into a String variable, that will be returned and put into a TextView in Android. I don't want the file to be written to sdcard, I just want to perform a memory operation.
For example, inside db.zip I have a file named packed.txt, which content is "Stack á é ç". The returned String in my method shows "83 116 97 99 107 32 195 161 32 (...)" which are the UTF-8 values for the characters. I tried so far converting'em to a human-readble form, but no success. Tried InputStreamReader but I couldn't make a correct use of it. My source-code is below.
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
import android.util.Log;
/**
*
* @author jon
*/
public class Decompress {
private String _zipFile;
private String _location;
public Decompress(String zipFile, String location) {
_zipFile = zipFile;
_location = location;
_dirChecker("");
}
public String unzip(String desiredFile) {
String strUnzipped = "";
try {
FileInputStream fin = new FileInputStream(_zipFile);
ZipInputStream zin = new ZipInputStream(fin);
ZipEntry ze = null;
while ((ze = zin.getNextEntry()) != null) {
Log.v("Decompress", "Unzipping " + ze.getName());
if(ze.isDirectory()) {
_dirChecker(ze.getName());
} else {
//FileOutputStream fout = new FileOutputStream(_location + ze.getName());
/**** Changes made below ****/
if (ze.getName().toString().equals(desiredFile)) {
byte[] bytes = new byte[(int) ze.getSize()];
if (zin.read(bytes, 0, bytes.length) == bytes.length) {
strUnzipped = new String(bytes, "UTF-8");
}
else {
strUnzipped = "Read error...";
}
/*** REMOVED
if (ze.getName() == desiredFile) {
for (int c = zin.read(); c != -1; c = zin.read()) {
strUnzipped += c;
//fout.write(c);
} */
}
zin.closeEntry();
//fout.close();
}
}
zin.close();
} catch(Exception e) {
Log.e("Decompress", "unzip", e);
}
return strUnzipped;
}
private void _dirChecker(String dir) {
File f = new File(_location + dir);
if(!f.isDirectory()) {
f.mkdirs();
}
}
}
解决方案
Sorry for my initial posting of this .... ran right over your paragraph stating you had tried this.
You can create the InputStreamReader with a charset of "UTF-8" which will automatically convert the input data into the correct characters for you.
while ((ze = zin.getNextEntry()) != null) {
Log.v("Decompress", "Unzipping " + ze.getName());
if(ze.isDirectory()) {
_dirChecker(ze.getName());
} else {
if (ze.getName() == desiredFile) {
byte[] bytes= new byte[ze.getSize()];
zin.read(bytes, 0, bytes.length);
strUnzipped= new String( bytes, "UTF-8" );
/* Removing this as it is easier to just read all the bytes in at once
InputStreamReader isr= new InputStreamReader(zin, "UTF-8");
char c= 0;
for (char c = isr.read(); c != -1; c = isr.read()) {
strUnzipped += c;
}
*/
}
zin.closeEntry();
}
}
Please try the above and see how it works out.
