我有一个EditText在我的应用程序，它是唯一的按钮，我已经放置在屏幕上接收输入。

I have an EditText in my application which is to only receive inputs from buttons I have placed on the screen.

要避免软键盘显示我有一个自定义的EditText类，如下所示：

To avoid the soft keyboard appearing I have a customised EditText class as follows:

public class CustomEditText extends EditText {

    public CustomEditText(Context context) {         
        super(context);
}

    public CustomEditText(Context context, AttributeSet attrs) {
        super(context, attrs);
    }

    @Override
    // Disables Keyboard;
    public boolean onCheckIsTextEditor() {
        return false;
    }   

}

此成功出现停止键盘，但在ICS这种方式也出现停止光标。

This successfully stops the keyboard from appearing, however in ICS this approach also stops the Cursor from appearing.

setCursorVisible（真）不产生任何影响。

我试着保持软键盘隐藏的替代方法，如使用机器人：编辑=假和 .setKeyListener（空）; ，但这些解决方案都曾经工作过的我的测试。总是出现键盘。

I've tried alternate methods of keeping the soft keyboard hidden, such as using android:editable="false" and .setKeyListener(null); but none of these solutions have ever worked in my tests. The keyboard always appears.

那么，有没有办法返回光标在ICS，同时保持onCheckIsTextEditor覆盖，因为它是？

So, is there a way to return the cursor in ICS, while keeping the onCheckIsTextEditor override as it is?

推荐答案

你为什么不尝试禁用按键垫像这样

why don't you try to disable soft key-pad like this

    //text field for input sequrity pin
    txtPin=(EditText) findViewById(R.id.txtpin);
    txtPin.setInputType(
      InputType.TYPE_CLASS_NUMBER | InputType.TYPE_TEXT_VARIATION_PASSWORD);
    txtPin.setSelection(txtPin.getText().length());
    txtPin.setTextSize(22);
    txtPin.setSingleLine(true);


    //disable keypad
    txtPin.setOnTouchListener(new OnTouchListener(){
        @Override
        public boolean onTouch(View v, MotionEvent event) {

              int inType = txtPin.getInputType(); // backup the input type
              txtPin.setInputType(InputType.TYPE_NULL); // disable soft input
              txtPin.onTouchEvent(event); // call native handler
              txtPin.setInputType(inType); // restore input type
                return true; // consume touch even
        }
        });

和这个领域的EditText

and for this EditText Field

<EditText android:layout_width="wrap_content" 
            android:id="@+id/txtpin"  
            android:maxLength="4" 
            android:layout_height="37dp" 
            android:gravity="center_horizontal" 
            android:longClickable="false" 
            android:padding="2dp"

            android:inputType="textPassword|number" 
            android:password="true" 
            android:background="@drawable/edittext_shadow" 
            android:layout_weight="0.98" 
            android:layout_marginLeft="15dp">
                <requestFocus></requestFocus>
   </EditText>

这是工作的罚款与我输入安全密码光标。

this is working fine with me for input security PIN with cursor.

我是从按钮没有键盘输入取

i am taking input from button not keypad.