setOnCheckedChangeListener(new OnCheckedChangeListener() {
            @Override
            public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
                // How to check whether the checkbox/switch has been checked
                // by user or it has been checked programatically ?

                if (isNotSetByUser())
                    return;
                handleSetbyUser();
            }
        });

如何实现方法 isNotSetByUser（）？

推荐答案

答2：

有一个很简单的回答：

使用的OnClickListener，而不是OnCheckedChangeListener

Use on OnClickListener instead of OnCheckedChangeListener

    someCheckBox.setOnClickListener(new OnClickListener(){

        @Override
        public void onClick(View v) {
            // you might keep a reference to the CheckBox to avoid this class cast
            boolean checked = ((CheckBox)v).isChecked();
            setSomeBoolean(checked);
        }

    });

现在您只需拿起点击事件，并且不担心方案变化。

Now you only pick up click events and don't have to worry about programmatic changes.

答1：

我创建了一个包装类（见修饰模式），该处理这个问题封装方式：

I have created a wrapper class (see Decorator Pattern) which handles this problem in an encapsulated way:

public class BetterCheckBox extends CheckBox {
private CompoundButton.OnCheckedChangeListener myListener = null;
private CheckBox myCheckBox;

public BetterCheckBox(Context context) {
    super(context);
}

public BetterCheckBox(Context context, CheckBox checkBox) {
    this(context);
    this.myCheckBox = checkBox;
}

    // assorted constructors here...    

@Override
public void setOnCheckedChangeListener(
    CompoundButton.OnCheckedChangeListener listener){
    if(this.myListener == null)
        this.myListener = listener;
    myCheckBox.setOnCheckedChangeListener(listener);
}

public void silentlySetChecked(boolean checked){
    toggleListener(false);
    myCheckBox.setChecked(checked);
    toggleListener(true);
}

private void toggleListener(boolean on){
    if(on){
        this.setOnCheckedChangeListener(myListener);
    }
    else
        this.setOnCheckedChangeListener(null);
}
}

复选框仍然可以宣布XML是相同的，但在code初始化你的GUI时，使用此：

CheckBox can still be declared the same in XML, but use this when initializing your GUI in code:

BetterCheckBox myCheckBox;

// later...
myCheckBox = new BetterCheckBox(context,
    (CheckBox) view.findViewById(R.id.my_check_box));

如果你想设置从code检查，而不触发听者代替，调用 myCheckBox.silentlySetChecked（someBoolean） setChecked 。

If you want to set checked from code without triggering the listener, call myCheckBox.silentlySetChecked(someBoolean) instead of setChecked.