假设你有一个像数组：

double[,] rectArray = new double[10,3];

现在你想要的fouth行作为3个元素的双重[]数组没有这样做的：

Now you want the fouth row as a double[] array of 3 elements without doing:

double[] fourthRow = new double[]{rectArray[3,0],
                                  rectArray[3,1], 
                                  rectArray[3,2]};

是否有可能好歹？即使使用Marshal.Something方法？

Is it possible someway? Even using a Marshal.Something approach?

谢谢！

推荐答案

LINQ救援：

var s = rectArray.Cast<double>().Skip(9).Take(3).ToArray();

说明：铸造一多维数组变平并将它与单个二维数组。之后，我们需要做的就是跳到我们想要的元素（2-D数组中的第4个元素解析为跳过（9）...），并采取3个元素，从它）。

Explanation: Casting a multi-dimensional array flattens it to a single-dimensional array. After that all we need to do is skip to the element we want (the 4th element in the 2-D array resolves to Skip(9)...) and take 3 elements from it).