我有一个返回产品列表的查询：

@Query(value = "Select * from Product join Product_Pro pp on Product.ID = pp.PRODUCT_ID where A_ID= ?1 order by name",
        nativeQuery = true)
    List<Product> findAll(long id);

如何向此添加LIKE子句？

当我在我的数据库中执行此语句时，得到一个结果：

Select * from Product join Product_Pro pp on Product.ID = pp.PRODUCT_ID where A_ID= ?1 AND name LIKE '%someString%' AND content LIKE '%someString%' order by name

但如何将LIKE添加到我的JPA本机查询？

我已尝试：

@Query(value = "Select * from Product join Product_Pro pp on Product.ID = pp.PRODUCT_ID where A_ID= ?1 and name LIKE '%?%' order by name",
            nativeQuery = true)
        List<Product> findAll(long id, String name);

和

@Query(value = "Select * from Product join Product_Pro pp on Product.ID = pp.PRODUCT_ID where A_ID= ?1 and name LIKE '%:name%' order by name",
            nativeQuery = true)
        List<Product> findAll(long id,@Param("name") String name);

但这些都不起作用。

推荐答案

我认为您需要CONCAT()：

and name LIKE CONCAT('%', ?2, '%')