简单的问题，我导入一个DLL函数，参数都为int *。 当我尝试输入方法（0），我得到一个错误，说：int和INT *不能将

simple question, I import a DLL function and the parameter are int*. When I try to enter Method(0), I get an error which says: "int and int* can not convert".

那是什么意思？

推荐答案

这是一个指向int经典的C表示法。每当类型后跟一个 * ，它指的类型作为的指针那个类型。在C＃中，不像在C，你必须明确定义功能不安全使用指针，除了启用的不安全 code。在项目属性。指针类型也不能直接互换的具体类型，这样类型的引用必须首先考虑。为了得到一个指向另一种类型，如int，在C＃（或C和C ++的这个问题），您必须使用引用操作＆安培; （符号）在变量前面你希望得到一个指向：

That is classic C notation for a pointer to an int. Whenever a type is followed by a *, it denotes that type as a pointer to that type. In C#, unlike in C, you must explicitly define functions as unsafe to use pointers, in addition to enabling unsafe code in your project properties. A pointer type is also not directly interchangeable with a concrete type, so the reference of a type must be taken first. To get a pointer to another type, such as an int, in C# (or C & C++ for that matter), you must use the dereference operator & (ampersand) in front of the variable you wish to get a pointer to:

unsafe
{
    int i = 5;
    int* p = &i;
    // Invoke with pointer to i
    Method(p);
}

不安全code C＃

下面是不安全code的一些关键文章，并在C＃中使用指针。

Below are some key articles on unsafe code and the use of pointers in C#.

不安全的环境 指针类型 固定和移动的变量 指针转换 指针在EX pressions 的固定的声明 堆栈分配 动态内存分配 Unsafe contexts Pointer Types Fixed and movable variables Pointer conversions Pointers in expressions The 'fixed' statement Stack allocation Dynamic memory allocation