在处理save()方法$ ngResource错误回调回调、错误、方法、save

2023-09-14 00:25:42 作者:太阳不及你暖心i

我需要处理更新操作的错误回调,对于这个我使用的方法保存()是这样的:

I need to handle error callback of an update operation, for this i'm using method save() like this:

$scope.save = function (params) {  
  MigParams.save(params);
};

Migparams 服务是这样的:

angular.module('monitor').
    factory('MigParams', function ($resource) {        
        return $resource('/restful/migparams');    
});

这code的伟大工程,但我需要如果数据库发生错误认识。我曾在谷歌搜索,但我没有找到这种特殊情况。有没有的得到这样的方式?在此先感谢

This code works great but i need to know if an error occurs in database. I have searched in google but i didn't find this particular case. Is there a way of get this?. Thanks in advance

推荐答案

的https: //docs.angularjs.org/api/ngResource/service/$resource :

非GET下课的行动:Resource.action([参数],POSTDATA,[成功],[错误])

non-GET "class" actions: Resource.action([parameters], postData, [success], [error])

非GET下课的实例:Resource.action([参数],[成功],[错误])

non-GET "class" instance: Resource.action([parameters], [success], [error])

$资源的保存方法分为非GET类的实例类),所以它的错误回调是第三个参数。

$resource's save method falls into the non-GET 'class' instance category), so its error callback is the third argument.

您code看起来像:

$scope.save = function (params) {  
  MigParams.save(params, 
    function(resp, headers){
      //success callback
      console.log(resp);
    },
    function(err){
      // error callback
      console.log(err);
    });
};