如何验证的IP，在AngularJS文本字段？目前我使用这个code，但它不是在所有情况下工作。任何想法？

ng-pattern='/^((([01]?[0-9]{1,2})|(2[0-4][0-9])|(25[0-5]))[.]){3}(([0-1]?[0-9]{1,2})|(2[0-4][0-9])|(25[0-5]))$/

使用：

匹配0.0.0.0通过255.255.255.255

如果您要删除 0.0.0.0 和 255.255.255.255 我建议你添加额外的如果语句。否则，正则表达式将是太复杂了。

的与守望示例：的

  $ scope.ip ='1.2.3.4';    $范围。$表（函数（）{        返回$ scope.ip;    }，    功能（的newval，OLDVAL）{        如果（            的newval ='0.0.0.0'和;！＆安培; ！的newval ='255.255.255.255'和;＆安培;            newVal.match(/\\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\b/))        {             //匹配尝试成功        }其他{            //匹配尝试失败        }    }） 

演示 小提琴

最好的办法是创造指令，是这样的：＆LT; IP输入＆GT;

这个例子可能有用如何创建自定义输入指令：format-input-value-in-angularjs

How to validate an IP in a text field in AngularJS ? Currently I'm using this code,but its not working in all cases . Any idea ?

ng-pattern='/^((([01]?[0-9]{1,2})|(2[0-4][0-9])|(25[0-5]))[.]){3}(([0-1]?[0-9]{1,2})|(2[0-4][0-9])|(25[0-5]))$/

Use:

/\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b/

Matches 0.0.0.0 through 255.255.255.255

If you want to drop 0.0.0.0 and255.255.255.255 I suggest you to add additional if statement. Otherwise the regex will be too complicated.

Example with watcher:

$scope.ip = '1.2.3.4';

    $scope.$watch(function () {
        return $scope.ip;
    },

    function (newVal, oldVal) {            
        if (
            newVal != '0.0.0.0' && newVal != '255.255.255.255' &&
            newVal.match(/\b(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\b/))
        {
             // Match attempt succeeded
        } else {
            // Match attempt failed
        }
    })

Demo Fiddle

[Edit]

The best bet is to create directive, something like: <ip-input>

This example might helpful how to create directive for custom input: format-input-value-in-angularjs