我使用的角度来创建搜索物业形态,我已经得到了与卧室量的选择框,我怎么可以创建一个大于过滤器? (例如:当选择2间卧室,显示有2间卧室或以上的所有属性)
I'm using angular to create a search property form, and I've got a select box with amount of bedrooms, how can I create a greater then filter? (for example: when 2 bedrooms selected, display all properties with 2 bedrooms or more)
该选择框:
<select class="form-control"
name="bedrooms"
ng-model="Bedrooms"
ng-options="property.data.SubType as (property.data.Bedrooms + ' Bedrooms ('+ property.count +')') for property in properties | unique:'Bedrooms' | orderBy:'data.Bedrooms'">
<option value="">Minimum Bedrooms</option>
</select>
和过滤器:
<tr ng-repeat="property in filtered = (properties | filterMultiple:{Address: Address, SubArea:SubArea, SubType:SubType} | filter:{Bedrooms:Bedrooms})| orderBy:Address">
这是我的的jsfiddle
http://jsfiddle.net/odpw6c6q / 43 /
在 NG-选项
使用 NG选项=property.data.Bedrooms为
而不是 NG选项=property.data.SubType为
因为 data.Bedrooms
是包含应存储在卧室号的属性NG-模型
In ng-options
use ng-options="property.data.Bedrooms as
instead of ng-options="property.data.SubType as
because data.Bedrooms
is the property that contains number of bedrooms which should be stored in ng-model
在范围添加此功能
//Filter Function
$scope.greaterThan = function(bedrooms) {
return function(item) {
if ( item['Bedrooms'] > bedrooms) {
return true;
} else {
return false;
}
}
};
在 NG-重复
使用过滤器:GREATERTHAN(卧室)
而不是过滤器: {卧室:卧室}