我想初始化的JSONObject与下面的字符串，从Web服务接收到的：

I'm trying to initialize a JSONObject with the following string, received from a web service:

"{
    "campaignid": "8",
    "campaignname": "Pilotarienak 2011",
    "campaignlink": "http:\\/\\/www.xxx.com\\/fr\\/cote-basque\\/agenda\\/2011-05-20\\/FMAAQU064FS016DV-pilotarienak-d-anglet?fromapp",
    "splash": "http:\\/\\/www.xxx.com\\/ads\\/customers\\/pilotarienak\\/320x480.jpg",
    "banner": "http:\\/\\/www.xxx.com\\/ads\\/customers\\/pilotarienak\\/320x160.jpg"
}"

这似乎是有效的JSON（它验证在jsonlint.com），但与初始化一个JSONObject的，当我得到：

It seems to be valid json (it validates in jsonlint.com), but when initializing a JSONObject with that I get:

org.json.JSONException: Value  of type java.lang.String cannot be converted to JSONObject

任何人都可以帮忙吗？

Anybody can help?

感谢

推荐答案

好像你正试图从额外引号中的字符串初始化它。您需要删除包装报价（我没有使用你的字符串，但举个例子，以使其更清晰）：

Seems like you are trying to instantiate it from a String with extra quotes. You need to remove the wrapping quotes(I'm not using your string, but giving an example to make it clearer):

这是确定：

String jStr= "{\"param1\":\"hello\"}";
JSONObject jObj = new JSONOBject(jStr);

这是不是：

String jStr= "\"{\"param1\":\"hello\"}\"";
//  note this ^^             and this ^^ 
JSONObject jObj = new JSONOBject(jStr);