异步任务来显示一个AlertDialog任务、AlertDialog
在过去的几天里，我一直没能解决的问题，我的对话框。我运行一个线程来显示5000毫秒对话框并删除它。我试图表现出吐司（SUCCESS）。问题是我得到的对话框中第二次也。我是新android开发，我需要解决这个与异步任务，这样我可以推迟第二个线程，并显示了积极的按钮而不是吐司警报dialog.builder。我瞪大眼睛了很多，但我困惑实现这个
在这里，我派我的凭据的服务器和在发送我表示5000毫秒进度对话框，我想有一个单独的线程，以示与积极的按钮dialog.builder。（当用户拿到反应在logcat中的，我应该检查响应code == 1或不从的logcat显示生成器）
PLZ有人能帮我解决这个有些code段如果可能的话。
在此先感谢。
这是在code，我需要实现异步任务
按钮的登入=（按钮）findViewById（R.id.regsubmitbtn）;
signin.setOnClickListener（新OnClickListener（）{
公共无效的onClick（视图v）{
//的ShowDialog（0）;
T =新的Thread（）{
公共无效的run（）{
寄存器（）;
尝试 {
而（计数器2）{
showmsg（0）;
视频下载（5000）;
removeDialog（0）;
// Toast.makeText（Register.thisRegisterd，Toast.LENGTH_LONG）.show（）;
showmsg（1）;
// toast.show（）;
视频下载（1000）;
}
}赶上（InterruptedException异常E）{
e.printStackTrace（）;
}
}
};
t.start（）;
}
}）;
}
@覆盖
受保护的对话框onCreateDialog（INT ID）{
开关（ID）{
情况下0：{
++计数器;
对话框=新ProgressDialog（本）;
如果（计数器== 1）{
dialog.setMessage（注册...）;
}
其他 {
字符串resultsRequestSOAP =;
如果（Log.v（TAG，将String.valueOf（resultsRequestSOAP））== 1）
;
{
上下文的背景下= getApplicationContext（）;
CharSequence的文字=Registerd;
INT持续时间= Toast.LENGTH_LONG;
吐司面包= Toast.makeText（背景，文本，持续时间）;
toast.show（）;
}
}
dialog.setIndeterminate（真正的）;
dialog.setCancelable（真正的）;
返回对话框;
}
}
返回null;
}
公共无效showmsg（INT actionsToBePerformedOnScreen）{
消息味精=新的Message（）;
msg.what = actionsToBePerformedOnScreen;
handler.sendMessage（MSG）;
}
公开处理程序处理程序=新的处理程序（）{
@覆盖
公共无效的handleMessage（信息MSG）{
开关（msg.what）{
情况下0：
的ShowDialog（0）;
打破;
情况1：
//清除列表中的所有图像
removeDialog（0）;
打破;
}
};
};
解决方案
很简单：显示对话框在preExecute ，寄存器（）在在和隐藏对话框。最后，执行 onPostExecute doInBackground 新RegisterTask（）。执行（）在的onclick 。
私有类RegisterTask扩展的AsyncTask＆LT;虚空，虚空，布尔＆GT; {
私人最终ProgressDialog对话框=新ProgressDialog（YourClass.this）;
在preExecute保护无效（）{
this.dialog.setMessage（登录...）;
this.dialog.show（）;
}
保护布尔doInBackground（最终虚空未使用）{
返回Main.this.register（）; //不与UI交互！
}
保护无效onPostExecute（最终布尔结果）{
如果（this.dialog.isShowing（））{
this.dialog.dismiss（）;
}
如果（result.booleanValue（））{
//还显示注册成功的对话框
}
}
}
For the past few days, I haven't been able to solve an issue with my dialog box. I am running a thread to show the dialog box for 5000ms and removing it. and I am trying to show a toast("SUCCESS"). The problem is I am getting the dialog box for the second time also. I am new to android development and I need to solve this with Async Task so that I can delay the second thread and show a alert dialog.builder with a positive button instead of toast. I goggled a lot but I confused to to implement this
Here I am sending my credentials to server and while sending I am showing a progress dialog box for 5000ms and I want to have a separate thread in order to show the dialog.builder with a positive button.( When the user get a response in the logcat for that I should check the responsecode==1 or not from the logcat to show the builder)
plz someone help me to solve this with some code snippet if possible.
Thanks in advance.
this is the code where I need to implement Async task
Button signin = (Button) findViewById(R.id.regsubmitbtn);
signin.setOnClickListener(new OnClickListener() {
public void onClick(View v) {
// showDialog(0);
t = new Thread() {
public void run() {
register();
try {
while (counter < 2) {
showmsg(0);
Thread.sleep(5000);
removeDialog(0);
// Toast.makeText(Register.this, "Registerd", Toast.LENGTH_LONG).show();
showmsg(1);
// toast.show();
Thread.sleep(1000);
}
} catch (InterruptedException e) {
e.printStackTrace();
}
}
};
t.start();
}
});
}
@Override
protected Dialog onCreateDialog(int id) {
switch (id) {
case 0: {
++counter;
dialog = new ProgressDialog(this);
if (counter == 1) {
dialog.setMessage("Registering...");
}
else {
String resultsRequestSOAP = "";
if (Log.v("TAG", String.valueOf(resultsRequestSOAP)) == 1)
;
{
Context context = getApplicationContext();
CharSequence text = "Registerd";
int duration = Toast.LENGTH_LONG;
Toast toast = Toast.makeText(context, text, duration);
toast.show();
}
}
dialog.setIndeterminate(true);
dialog.setCancelable(true);
return dialog;
}
}
return null;
}
public void showmsg(int actionsToBePerformedOnScreen) {
Message msg = new Message();
msg.what = actionsToBePerformedOnScreen;
handler.sendMessage(msg);
}
public Handler handler = new Handler() {
@Override
public void handleMessage(Message msg) {
switch (msg.what) {
case 0:
showDialog(0);
break;
case 1:
// clear all images in the list
removeDialog(0);
break;
}
};
};
解决方案
Easy: show dialog onPreExecute, register() in doInBackground and hide dialog in onPostExecute. Finally, do new RegisterTask().execute() in your onclick.
private class RegisterTask extends AsyncTask<Void, Void, Boolean> {
private final ProgressDialog dialog = new ProgressDialog(YourClass.this);
protected void onPreExecute() {
this.dialog.setMessage("Signing in...");
this.dialog.show();
}
protected Boolean doInBackground(final Void unused) {
return Main.this.register(); //don't interact with the ui!
}
protected void onPostExecute(final Boolean result) {
if (this.dialog.isShowing()) {
this.dialog.dismiss();
}
if (result.booleanValue()) {
//also show register success dialog
}
}
}
