我要求输入用户通过一个对话框：

I am asking the user for input via a Dialog:

package com.android.cancertrials;

import android.app.Dialog;
import android.content.Context;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class CustomDialog extends Dialog  {


    private String name;
//    private ReadyListener readyListener;
     public static EditText etName;
     public String zip;

    public CustomDialog(Context context, String name) {
        super(context);
        this.name = name;
//        this.readyListener = readyListener;
    }

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.mycustomdialog);
        setTitle("Enter the Zip Code ");
        Button buttonOK = (Button) findViewById(R.id.ok);
        buttonOK.setOnClickListener(new OKListener());
        etName = (EditText) findViewById(R.id.EditZip);
    }

    private class OKListener implements android.view.View.OnClickListener {
        @Override
        public void onClick(View v) {
//            readyListener.ready(String.valueOf(etName.getText()));
            CustomDialog.this.dismiss();
        }
    }


}

当用户点击OK，我怎么能传递被输入在文本框中的值，返回到启动它的活动成员变量？

When the user hits OK, how can I pass the value that was entered in the textbox, back to a member variable in the Activity that launched it?

推荐答案

您可以做，以不同的方式......实际上，如果你的对话框只有一个确定按钮退出，你为什么不只是创建使用自定义对话框中的 AlertDialog.Builder 类而不是子类对话框？

You can do that in different ways... actually, if your dialog has only an "OK" button to dismiss, why don't you just create a custom dialog using the AlertDialog.Builder class instead of subclassing Dialog?

反正...让我们假设你有充分的理由这样做你做的方式。在这种情况下，我会使用ObserverPattern。事情是这样的：

Anyway... let's suppose you have good reasons to do it the way you did it. In that case, I'd use the ObserverPattern. Something like this:

public class CustomDialog extends Dialog  {


    private String name;
     public static EditText etName;
     public String zip;
    OnMyDialogResult mDialogResult; // the callback

    public CustomDialog(Context context, String name) {
        super(context);
        this.name = name;
    }

    @Override
    public void onCreate(Bundle savedInstanceState) {
        // same you have
    }

    private class OKListener implements android.view.View.OnClickListener {
        @Override
        public void onClick(View v) {
            if( mDialogResult != null ){
                mDialogResult.finish(String.valueOf(etName.getText()));
            }
            CustomDialog.this.dismiss();
        }
    }

    public void setDialogResult(OnMyDialogResult dialogResult){
        mDialogResult = dialogResult;
    }

    public interface OnMyDialogResult{
       void finish(String result);
    }
}

在你的活动：

CustomDialog dialog;
// initialization stuff, blah blah
dialog.setDialogResult(new OnMyDialogResult(){
    public void finish(String result){
        // now you can use the 'result' on your activity
    }
});

读你的code，看来你已经尝试过类似的事情。

Reading your code it seems you already tried something similar.

您仍然可以使用你的 mycustomdialog 的布局。这是你将如何使用 AlertDialog.Builder ：

You can still use your mycustomdialog layout. And this is how you would use the AlertDialog.Builder:

LayoutInflater inflater = LayoutInflater.from(YourActivity.this);
final View yourCustomView = inflater.inflate(R.layout.mycustomdialog, null);

final TextView etName = (EditText) yourCustomView.findViewById(R.id.EditZip);
AlertDialog dialog = new AlertDialog.Builder(YourActivity.this)
    .setTitle("Enter the Zip Code")
    .setView(yourCustomView)
    .setPositiveButton("OK", new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int whichButton) {
            mSomeVariableYouHaveOnYourActivity = etName.getText().toString();
        }
    })
    .setNegativeButton("Cancel", null).create();
dialog.show();