选择一个号码和名称从Android应用程序的联系人列表应用程序、联系人、号码、名称

2023-09-12 02:22:08 作者:你不是怪胎

我想选择一个与它接触是从我的联系人列表号。 我读了很多的解决方案,并研究几个星期,但所有的文章都不能正常工作。 一些codeS类似如下:

i want to pick a contact with it's number from my contacts list. i read a lot of solutions and research for couple weeks but all of articles didn't work properly. some codes like following:

Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
startActivityForResult(intent, PICK_CONTACT);

//和activityresult:

// and in activityresult:

if (resultCode == Activity.RESULT_OK) {
            Uri contactData = data.getData();
            Cursor c =  managedQuery(contactData, null, null, null, null);
            if (c.moveToFirst()) {
              String name = c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts.DISPLAY_NAME));
              tv1.setText(name);
            }
          }

或此code获取的所有联系人,但我不能有触点数量:

or this code for getting all contacts but i cant have the number of contacts:

String[] contacts = new String[] {People.NAME, People.NUMBER};       
Uri contentUri = People.CONTENT_URI;        
Cursor cursor = managedQuery(contentUri, contacts, null, null, null);                 
String textContacts = "";                 
if (cursor.moveToFirst()) {         
    String myname = null;         
    String mynumber = null;         
    do {          
        textContacts = textContacts + cursor.getString(cursor.getColumnIndex(People.NAME)) + " : " + cursor.getString(cursor.getColumnIndex(People.NUMBER)) + "\n";         
    } while (cursor.moveToNext()); 
tv1.setText(textContacts);
}

谁能帮助我PLZ?我的Andr​​oid 2.3.3是

can anyone help me plz? my android is 2.3.3

推荐答案

试试下面的code它会帮助你。

Try following code it will help you

  // Declare
  static final int PICK_CONTACT=1;

  Intent intent = new Intent(Intent.ACTION_PICK, ContactsContract.Contacts.CONTENT_URI);
  startActivityForResult(intent, PICK_CONTACT);

  //code 
  @Override
 public void onActivityResult(int reqCode, int resultCode, Intent data) {
 super.onActivityResult(reqCode, resultCode, data);

 switch (reqCode) {
 case (PICK_CONTACT) :
   if (resultCode == Activity.RESULT_OK) {

     Uri contactData = data.getData();
     Cursor c =  managedQuery(contactData, null, null, null, null);
     if (c.moveToFirst()) {


         String id =c.getString(c.getColumnIndexOrThrow(ContactsContract.Contacts._ID));

         String hasPhone =c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER));

           if (hasPhone.equalsIgnoreCase("1")) {
          Cursor phones = getContentResolver().query( 
                       ContactsContract.CommonDataKinds.Phone.CONTENT_URI,null, 
                       ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ id, 
                       null, null);
             phones.moveToFirst();
              cNumber = phones.getString(phones.getColumnIndex("data1"));
             System.out.println("number is:"+cNumber);
           }
         String name = c.getString(c.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));


     }
   }
   break;
 }
 }