Android的资源 - 数组的数组数组、资源、Android

2023-09-12 01:05:30 作者:秀不羁

我想实现资源数据结构包括一个数组的数组,特别是字符串。我遇到的问题是如何让子阵列对象及其具体数值。这里是我的资源文件看起来像......

I am trying to implement a resource data structure that includes an array of arrays, specifically strings. The issue I run into is how to get the sub-array objects and their specific values. Here is what my resource file looks like....

<resources>
   <array name="array0">
     <item>
       <string-array name="array01">
         <item name="id">1</item>
         <item name="title">item one</item>
       </string-array>
     </item>
     <item>
       <string-array name="array02">
         <item name="id">2</item>
         <item name="title">item two</item>
       </string-array>
     </item>
     <item>
       <string-array name="array03">
         <item name="id">3</item>
         <item name="title">item three</item>
       </string-array>
     </item>
   </array>
</resources>

于是,在我的Java code我找回阵列和尝试访问的子元素,像这样......

Then, in my Java code I retrieve the array and try to access the sub elements like so...

TypedArray typedArray = getResources().obtainTypedArray(R.array.array0);

TypedValue typedValue = null;

typedArray.getValue(0, typedValue);

在这一点上typedArray对象应重新present字符串数组array01,但我看不出如何检索ID和称号字符串元素。任何帮助将是AP preciated,在此先感谢。

At this point the typedArray object should represent the string-array "array01", however, I don't see how to retrieve the "id" and "title" string elements. Any help would be appreciated, thanks in advance.

推荐答案

您几乎可以做你想做的。你必须单独申报每个数组,然后引用数组。事情是这样的:

You can almost do what you want. You have to declare each array separately and then an array of references. Something like this:

<string-array name="array01">
    <item name="id">1</item>
    <item name="title">item one</item>
</string-array>
<!-- etc. -->
<array name="array0">
    <item>@array/array01</item>
    <!-- etc. -->
</array>

然后在你的code,你做这样的事情:

Then in your code you do something like this:

Resources res = getResources();
TypedArray ta = res.obtainTypedArray(R.array.array0);
int n = ta.length();
String[][] array = new String[n][];
for (int i = 0; i < n; ++i) {
    int id = ta.getResourceId(i, 0);
    if (id > 0) {
        array[i] = res.getStringArray(id);
    } else {
        // something wrong with the XML
    }
}
ta.recycle(); // Important!
 
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