这是我的JSON字符串(动态这改变):
这是从整个JSON字符串这是一个阵列中的一个JSON对象。 如果JSON对象具有大于1的值为ChildExists(例如4象下面),阵列被称为关键字出现和4个对象将被显示。如果任何对象的childExist值变得大于1,JSON数组被称为分类将出现。
这会发生一遍又一遍,如果为childExists对象的值大于0,我创建了2模型类为这个具有以下属性:
公共类菜单实现Serializable {
私有静态最后长的serialVersionUID = -3407147461924698222L;
字符串parentName;
字符串的位置;
字符串childExists;
字符串categoryName;
字符串categoryId;
字符串的parentID;
名单<类别>类别=新的ArrayList<类别>();
// getter和setter
}
公共类分类实现Serializable {
私有静态最后长的serialVersionUID = -3407147461924698222L;
字符串parentName;
字符串的位置;
字符串childExists;
字符串categoryName;
字符串categoryId;
字符串的parentID;
// getter和setter
}
这是我如何试图打破JSON:
公共静态的ArrayList<菜单> getMenuTreeBreakDown(JSONArray为arg0)抛出JSONException {
ArrayList的<菜单>菜单列表=新的ArrayList<菜单>();
的for(int i = 0; I< arg0.length();我++){
的JSONObject jsonCategoryObject = arg0.getJSONObject(ⅰ);
菜单菜单=新菜单();
串parentName = jsonCategoryObject.getString(ParentName);
字符串的位置= jsonCategoryObject.getString(位置);
串childExists = jsonCategoryObject.getString(ChildExists);
字符串categoryName = jsonCategoryObject.getString(CATEGORY_NAME);
字符串categoryId = jsonCategoryObject.getString(CATEGORY_ID);
串的parentID = jsonCategoryObject.getString(PARENT_ID);
menu.setParentName(parentName);
menu.setPosition(位置);
menu.setChildExists(childExists);
menu.setCategoryName(类别名);
menu.setCategoryID(的categoryID);
menu.setParentID(的parentID);
如果(!childExists.equalsIgnoreCase(0)){
//这部分应该发生一遍又一遍,如果还有一类是[]
JSONArray categoryArray =新JSONArray(jsonCategoryObject.getString(分类));
为(中间体X = 0 X - 其中; categoryArray.length(); X ++){
JSONObject的jsonProductObject1 = categoryArray.getJSONObject(X);
类别类别=新类别();
category.setParentName(jsonProductObject1.getString(ParentName));
category.setPosition(jsonProductObject1.getString(位置));
category.setChildExists(jsonProductObject1.getString(ChildExists));
category.setCategoryName(jsonProductObject1.getString(CATEGORY_NAME));
category.setCategoryID(jsonProductObject1.getString(CATEGORY_ID));
category.setParentID(jsonProductObject1.getString(PARENT_ID));
。menu.getCategories()加(类);
}
}
menuList.add(菜单);
}
返回菜单列表;
}
到目前为止,我无法得到正确的结果。任何帮助是极大AP preciated!
//得到这个工作:
用于GSON,改变了模型类:
公共类菜单{
@SerializedName(ParentName)
字符串parentName;
@SerializedName(位置)
字符串的位置;
@SerializedName(ChildExists)
字符串childExists;
@SerializedName(CATEGORY_NAME)
字符串categoryName;
@SerializedName(CATEGORY_ID)
字符串categoryId;
@SerializedName(PARENT_ID)
字符串的parentID;
@SerializedName(分类)
名单<菜单>类别=新的ArrayList<菜单>();
// getter和setter
}
ArrayList的<菜单>菜单列表=新的ArrayList<菜单>();
GSON GSON =新GSON();
JsonParser分析器=新JsonParser();
。JsonArray jArray = parser.parse(arg0.toString())getAsJsonArray();
对于(JsonElement OBJ:jArray)
{
菜单菜单= gson.fromJson(OBJ,Menu.class);
menuList.add(菜单);
}
解决方案
你调试和检查确切部位在哪里突破?
使用for each循环在那里你可以,而不是为(;;)
http://docs.oracle.com/ JavaSE的/ 1.5.0 /文档/引导/语言/ foreach.html
如何在Java for each循环的工作?
另外,如果你有一个复杂的JSON,您可以使用GSON地图数据和模型类会更好。例如:
GSON GSON =新GSON();
ModelClass modelClass =新ModelClass();
modelClass = gson.fromJson(responseContent,ModelClass.class);
//其中,responseContent是你的jsonString
Log.i(Web服务响应,+ modelClass.toString());
的https://$c$c.google.com/p/google -gson /
有关命名差异(根据在web服务中的变量),可以使用像注解 @SerializedName。 (所以没有必要使用序列化)
This is my JSON String (this changes dynamically):
This is one json object from the entire json string which is an array. If the JSON object has value greater than 1 for "ChildExists" (for example 4 like below), an array called "Categories" appears and 4 objects will be shown. If the childExist value of any of those objects become greater than 1, a json array called "Categories" will appear.
This will happen over and over again if the object's value for "childExists" is greater than 0. I created 2 model classes for this with the following attributes :
public class Menu implements Serializable{
private static final long serialVersionUID = -3407147461924698222L;
String parentName;
String position;
String childExists;
String categoryName;
String categoryID;
String parentID;
List<Category> categories = new ArrayList<Category>();
//getters and setters
}
public class Category implements Serializable{
private static final long serialVersionUID = -3407147461924698222L;
String parentName;
String position;
String childExists;
String categoryName;
String categoryID;
String parentID;
//getters and setters
}
This is how I tried to break down the json:
public static ArrayList<Menu> getMenuTreeBreakDown(JSONArray arg0) throws JSONException {
ArrayList<Menu> menuList = new ArrayList<Menu>();
for(int i = 0; i < arg0.length(); i++){
JSONObject jsonCategoryObject = arg0.getJSONObject(i);
Menu menu = new Menu();
String parentName = jsonCategoryObject.getString("ParentName");
String position = jsonCategoryObject.getString("Position");
String childExists = jsonCategoryObject.getString("ChildExists");
String categoryName = jsonCategoryObject.getString("Category_Name");
String categoryID = jsonCategoryObject.getString("Category_ID");
String parentID = jsonCategoryObject.getString("Parent_ID");
menu.setParentName(parentName);
menu.setPosition(position);
menu.setChildExists(childExists);
menu.setCategoryName(categoryName);
menu.setCategoryID(categoryID);
menu.setParentID(parentID);
if(!childExists.equalsIgnoreCase("0")){
//this part should happen over and over again if there is a category[]
JSONArray categoryArray = new JSONArray(jsonCategoryObject.getString("Categories"));
for (int x = 0; x < categoryArray.length(); x++){
JSONObject jsonProductObject1 = categoryArray.getJSONObject(x);
Category category = new Category();
category.setParentName(jsonProductObject1.getString("ParentName"));
category.setPosition(jsonProductObject1.getString("Position"));
category.setChildExists(jsonProductObject1.getString("ChildExists"));
category.setCategoryName(jsonProductObject1.getString("Category_Name"));
category.setCategoryID(jsonProductObject1.getString("Category_ID"));
category.setParentID(jsonProductObject1.getString("Parent_ID"));
menu.getCategories().add(category);
}
}
menuList.add(menu);
}
return menuList;
}
So far I could not get the correct results. Any help is greatly appreciated!
//got this working:
Used GSON, changed the model class:
public class Menu{
@SerializedName("ParentName")
String parentName;
@SerializedName("Position")
String position;
@SerializedName("ChildExists")
String childExists;
@SerializedName("Category_Name")
String categoryName;
@SerializedName("Category_ID")
String categoryID;
@SerializedName("Parent_ID")
String parentID;
@SerializedName("Categories")
List<Menu> categories = new ArrayList<Menu>();
//getters and setters
}
ArrayList<Menu> menuList = new ArrayList<Menu>();
Gson gson = new Gson();
JsonParser parser = new JsonParser();
JsonArray jArray = parser.parse(arg0.toString()).getAsJsonArray();
for(JsonElement obj : jArray )
{
Menu menu = gson.fromJson( obj , Menu.class);
menuList.add(menu);
}
解决方案
Did you debug and check where exactly does it break?
Use a for each loop where you can instead of for(;;)
http://docs.oracle.com/javase/1.5.0/docs/guide/language/foreach.html
How does the Java for each loop work?
Also, If you have a complicated json, you may be better off using Gson to map data and your model classes. Eg.:
Gson gson = new Gson();
ModelClass modelClass= new ModelClass();
modelClass= gson.fromJson(responseContent,ModelClass.class);
//where responseContent is your jsonString
Log.i("Web service response", ""+modelClass.toString());
https://code.google.com/p/google-gson/
For Naming discrepancies(according to the variables in webservice), can use annotations like @SerializedName. (So no need to use Serializable)