我想设计的应用程序，显示无线网络列表提供连接到网络时选择它。我已经实现了部分显示的扫描结果。现在我想连接到由从扫描结果列表中的用户选择一个特定的网络。 谁能告诉我该怎么做呢？

I want to design an app which shows a list of wifi networks available and connect to the network when it is selected. I have implemented the part showing the scan results. Now i want to connect to a particular network selected by the user from the list of scan results. Can anyone please tell me how to do this?

推荐答案

您需要创建这样的WifiConfiguration例如：

You need to create WifiConfiguration instance like this:

String networkSSID = "test";
String networkPass = "pass";

WifiConfiguration conf = new WifiConfiguration();
conf.SSID = "\"" + networkSSID + "\"";   // Please note the quotes. String should contain ssid in quotes

然后，WEP的网络，你需要做的：

Then, for WEP network you need to do this:

conf.wepKeys[0] = "\"" + networkPass + "\""; 
conf.wepTxKeyIndex = 0;
conf.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.NONE);
conf.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.WEP40); 

有关WPA网络，你需要添加密码是这样的：

For WPA network you need to add passphrase like this:

conf.preSharedKey = "\""+ networkPass +"\"";

有关开放式的网络，你需要做的：

For Open network you need to do this:

conf.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.NONE);

然后，你需要将它添加到Android的WiFi管理器设置：

Then, you need to add it to Android wifi manager settings:

WifiManager wifiManager = (WifiManager)context.getSystemService(Context.WIFI_SERVICE); 
wifiManager.addNetwork(conf);

最后，您可能需要启用它，因此Android连接到它：

And finally, you might need to enable it, so Android connects to it:

List<WifiConfiguration> list = wifiManager.getConfiguredNetworks();
for( WifiConfiguration i : list ) {
    if(i.SSID != null && i.SSID.equals("\"" + networkSSID + "\"")) {
         wifiManager.disconnect();
         wifiManager.enableNetwork(i.networkId, true);
         wifiManager.reconnect();               

         break;
    }           
 }

UPD：如果WEP，如果你的密码是十六进制，你不需要用引号括起来。

UPD: In case of WEP, if your password is in hex, you do not need to surround it with quotes.