这是在code，我从

import sys
import boto
import boto.s3

# AWS ACCESS DETAILS
AWS_ACCESS_KEY_ID = ''
AWS_SECRET_ACCESS_KEY = ''

bucket_name = AWS_ACCESS_KEY_ID.lower() + '-mah-bucket' conn = boto.connect_s3(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY)
bucket = conn.create_bucket(bucket_name, location=boto.s3.connection.Location.DEFAULT)
uploadfile = sys.argv[1]

print 'Uploading %s to Amazon S3 bucket %s' % \
       (uploadfile, bucket_name)

def percent_cb(complete, total):
    sys.stdout.write('.')
    sys.stdout.flush()

from boto.s3.key import Key
k = Key(bucket)
k.key = 'my test file'
k.set_contents_from_filename(testfile, cb=percent_cb, num_cb=10)

在我的S3我已经创建了目录，这样的水桶/图片/假日。我知道这些只是虚拟目录。

On my S3 I have created "directories", like this "bucket/images/holiday". I know these are only virtual directories.

我的问题是，我怎么能修改此上传专门桶/图片/假期的虚拟目录在S3上，而不是斗根？

My question is, how can I modify this upload specifically to bucket/images/holiday virtual directory on S3 rather than the bucket root?

推荐答案

所有你应该做的是prePEND虚拟目录路径之前上传的键名。例如：

All you should have to do is prepend the virtual directory path to the key name prior to uploading. For example:

key_name = 'my test file'
path = 'images/holiday'
full_key_name = os.path.join(path, key_name)
k = bucket.new_key(full_key_name)
k.set_contents_from_filename(...)

您可能需要更改该位为你的应用程序，但希望这给你的基本思路。

You may have to change that a bit for your application but hopefully that gives you the basic idea.