我想生成从 0 到大小的指标 - 1 ，均匀，但比指数不同在给定的排除。

尺寸约为100通常有1，2或3 已排除指数。在排除指数是独一无二的，没有排序。

在理想情况下，头会随着多个参数，也许是这样的：

  INT getRandomIndex（随机兰特，诠释大小，INT ... I）
 

或者，如果该 ... 多参数是缓慢的（是吗？），我们可以通过简单的 INT []排除数组或什么的。

怎么做快？ getRandomIndex（）被称为数百万次。

 静态INT getRandomIndex（随机兰特，诠释大小，整数...排除）{
    名单＆LT;整数GT; excludeList = Arrays.asList（不含）;
    INT编号;
    做 {
        数= rand.nextInt（大小）;
    }而（excludeList.contains（数））;

    返回数;
}
 

I would like to generate an index from 0 to size - 1, uniformly, but different than any index in the given set excluded.

size is around 100. There are typically 1, 2 or 3 exluded indices. Indices in excluded are unique and not sorted.

Ideally, the header will be with multiple arguments, maybe something like this:

int getRandomIndex(Random rand, int size, int... i)

Or, if this ... multi arguments are slow (are they?) we can pass simple int[] excluded array or something.

How to do it fast? getRandomIndex() is called millions of times.

static int getRandomIndex(Random rand, int size, Integer... excludes) {
    List<Integer> excludeList = Arrays.asList(excludes);
    int number;
    do {
        number = rand.nextInt(size);
    } while (excludeList.contains(number));

    return number;
}