说我有5×5的栅格，并在从0-24编号网格每个单元，打算从左至右。给定一个手机号码，如17，我该如何确定，该单元的X和Y坐标？我已经能够做到这一点，反之亦然，在那里，如果给出的坐标，我可以计算出细胞数：

Say I have a grid of 5x5, with each cell in the grid numbered from 0-24, going from left to right. Given a cell number such as 17, how do I determine that cell's x and y coordinates? I've been able to do it vice versa, where if given the coordinates I can calculate cell number:

Cellnumber = X + Y *宽度 （x和y坐标重新present左上点每个电池单元的）

Cellnumber = x + y∗width (The x and y coordinates represent the upper left point of each cell)

但现在我想的正好相反。任何想法？

But now I want the opposite. Any ideas?

推荐答案

假设基于0的坐标和一个类似C的语法，这将是这样的：

Assuming 0-based coordinates and a C-like syntax, it would be something like this:

int y = Cellnumber / width;
int x = Cellnumber % width;