我产生了一种隧道，你可以飞通过，在2D画面。我想在墙上顺利从左侧移动到右随机。现在，我刚刚结束了尖峰。

I'm generating a sort of tunnel that you can fly through, in a 2D screen. I want the walls to smoothly move from left to right randomly. Right now I just end up with "spikes".

我希望它看起来像这样

而不是这个

我用$ C $下看起来像这样的墙壁，四十次，每次左右。

I'm using code for the walls that looks like this, forty times each left and right.

if (Left1.center.y > 568) {
    RandomPosition = arc4random() %55;
    Left1.center = CGPointMake(RandomPosition, 0);
    RandomPosition = RandomPosition + 265;
    Right1.center = CGPointMake(RandomPosition, 0);
}

然后将此

RandomPosition = arc4random() %55;
Left1.center = CGPointMake(RandomPosition, 0);
RandomPosition = RandomPosition + 265;
Right1.center = CGPointMake(RandomPosition, 0);

但它并没有真正移动的墙壁就是我想要的。

but it doesnt really move the walls the way I want.

推荐答案

你要找的是所谓的相关性是什么产生随机数。

What you're looking for is called "correlated" random number generation.

一个产生这些数字的最流行的方式被称为 Perlin杂< /一>，这可能是太复杂了您的需求。

One of the most popular ways of generating such numbers is called Perlin noise, which may be too complicated for your needs.

做你的情况最简单的事情是跟踪的最后一个墙的位置，并生成一个随机的偏移的从，而不是被用于的裸值数发生器壁。这被称为一个随机或醉步行的

The simplest thing to do in your case would be to keep track of the last wall position, and generate a random offset from that, instead of the number generator being used for the bare value of the wall. This is known as a "random" or "drunken" walk.

要保持隧道的宽度相同，随机选择只有左墙的终点，然后把右壁结束了正确的距离。

To keep the tunnel's width the same, randomly pick only the left wall's end point, then put the right wall's end the correct distance away.

CGFloat leftWallX = /* starting value */;
for( int i = 0; i < NUM_WALLS; i++ ){
    // Generate a number from -MAX_OFFSET to MAX_OFFSET
    CGFloat offset = (CGFloat)arc4random_uniform(2*MAX_OFFSET) - MAX_OFFSET;
    leftWallX += offset;
    rightWallX = leftWallX + tunnelWidth;
    //...
}