Laravel AJAX请求不工作的方法的宁静控制器。
这AJAX请求不起作用上创建方法,但它的工作原理上laravel资源控制器的指数方法。
第一个链接的工作,因为它是指数法。而第二个环节是创建一个不能正常工作的方法。这两个code是相同的。
http://thetoppinghouse.com/laravel/public/listing http://thetoppinghouse.com/laravel/public/listing/create
在这里,你会得到我的code汇总 http://laravel.io/bin/roYBY
我已经张贴在这里没有活生生的例子了这个问题,但不能得到解决方案。 Laravel Ajax请求不工作控制器的
下面是我的AJAX code摘要
// AJAX Requesst
<脚本>
$('#PARENT_ID')。在('改变',功能(五){
执行console.log(E);
VAR cat_id = e.target.value;
// AJAX
$获得('AJAX-subcat?cat_id ='+ cat_id,功能(数据){
$('#子类别)空();
$每个(数据,函数(指数,subcatObj){
$('#子类别)追加('<期权价值=+ subcatObj.id +'>+ subcatObj.name +'< /选项>')
});
的console.log(数据);
});
});
< / SCRIPT>
和路线是在这里
// routes.php文件
路线::资源('上市','ListingController');
路线::得到('AJAX-subcat',函数(){
$ cat_id =输入::获得(cat_id);
$子类别=子目录::其中('PARENT_ID','=',$ cat_id) - >获得();
返回响应:: JSON($亚类);
});
解决方案
问题是,你的JavaScript code是使Ajax请求 AJAX-subcat?cat_id = 1
,一个相对的URL。这意味着:
/ laravel /公/上市=> / laravel /公/ AJAX-subcat
/ laravel /公/上市/创建=> / laravel /公/上市/ AJAX-subcat
既然你已经有你的JavaScript刀片模板中,你可以很容易地让Laravel生成的网址:
// AJAX
$获得({{网址::以('AJAX-subcat')}}?cat_id ='+ cat_id,功能(数据){
$('#子类别)空();
Laravel AJAX Request not working of a restful controller of a method.
This AJAX request does not work on create method but it works on index method of a laravel resource controller.
The first link is worked as it is index method. And the second link is create method which does not work. Both code are same
http://thetoppinghouse.com/laravel/public/listing http://thetoppinghouse.com/laravel/public/listing/create
Here you will get my code summary http://laravel.io/bin/roYBY
I have already post this question without live example here but could not get solution. Laravel Ajax request not working of a controller
Here is my AJAX code summary
// AJAX Requesst
<script>
$('#parent_ID').on('change',function(e){
console.log(e);
var cat_id = e.target.value;
// AJAX
$.get('ajax-subcat?cat_id=' + cat_id, function(data){
$('#subcategory').empty();
$.each(data, function(index, subcatObj){
$('#subcategory').append('<option value="'+subcatObj.id+'">'+subcatObj.name+'</option>')
});
console.log(data);
});
});
</script>
And routes is here
// routes.php
Route::resource('listing','ListingController');
Route::get('ajax-subcat', function(){
$cat_id = Input::get('cat_id');
$subcategories = Subcategory::where('parent_ID', '=', $cat_id)->get();
return Response::json($subcategories);
});
解决方案
The problem is that your javascript code is making the ajax request to ajax-subcat?cat_id=1
, a relative URL. This means:
/laravel/public/listing => /laravel/public/ajax-subcat
/laravel/public/listing/create => /laravel/public/listing/ajax-subcat
Since you already have your javascript inside the blade template you can easily let Laravel generate the URL:
// AJAX
$.get('{{ URL::to('ajax-subcat') }}?cat_id=' + cat_id, function(data){
$('#subcategory').empty();