我怎样才能捕捉到JavaScript的PHP的会话变量不刷新页面？变量、捉到、页面、PHP
我有一个的index.php ，在那里我做在session_start（）等。登录，我发Ajax请求 receiver.php ，在这里我设置会话变量等，并得到一个Ajax响应了。
I have an index.php, where I do session_start() etc. For login, I send an ajax request to receiver.php, where I set the session variables etc and get an ajax response back.
现在，我可以完美地捕捉到PHP的会话变量的的只有当我刷新的的的index.php 页有以下code：
Now, I can perfectly capture the php session variables only when I refresh the index.php page that has the following code:
jsSessionUserId = <?php
if (isset($_SESSION['userId'])) { //LoggedIn:
echo json_encode($_SESSION['userId']);
} else { // Not logged in.
// some code here
}
?>;
我真正想要的是，当我收到一个成功的Ajax响应（因此没有必要刷新的index.php 页）。这是行不通的。我怀疑是PHP不相当的javascript函数内的工作。感谢您的任何帮助。
What I really want is to put this in a function and then call this function when I receive a successful ajax response (and thus not have the need to refresh the index.php page). It is not working. I suspect that the php doesn't quite work inside of a javascript function. Grateful for any help.
推荐答案
这是坏主意混为一谈。像PHP和JavaScript。你最简单的解决方案，现在 - 一旦收到成功登录响应覆盖您的JavaScript变量
It is bad idea to mix things up. Like php and javascript. Easiest solution for you right now - overwrite your javascript variables once successful login response is received.
$.post("receiver.php", formData, function(response){ // login callback
if(response.UserId){ // return user id if login is successful
jsSessionUserId = response.UserId; // overwrite old variable
}
}, "json");
