我如何使用一个外部变量我
里面的阿贾克斯成功?
例如:
为(i = 0;我3; ++ I){
$阿贾克斯({
键入:POST,
数据:用户= 132,
网址:../php/order_ajax.php
成功:功能(数据){
$('。OBJ'+ I)。html的(数据);
}
});
}
解决方案
您应该关闭它在例如匿名函数。这是因为Ajax调用是异步的,我敢打赌,你甚至在第一个ajax调用完成,这意味着我将是4到那个时候这个循环就结束了。
VAR用户= 1;
为(ⅰ= 0;我3; ++ⅰ){
(函数(ⅰ){
$阿贾克斯({
键入:POST,
数据:用户=+用户,
网址:../php/order_ajax.php
成功:功能(数据){
$('。OBJ'+ I)。html的(数据);
}
});
})(一世);
}
How can I use an external variable i
inside the Ajax success?
For example:
for (i = 0; i < 3; ++i) {
$.ajax({
type: "POST",
data: "user=132",
url: "../php/order_ajax.php",
success: function(data){
$('.obj' + i).html(data);
}
});
}
解决方案
you should close it in for example anonymous function. It is because ajax call is asynchronous and I bet you that loop is finished even before the first ajax call is done which means that "i" will be 4 by that time.
var user = 1;
for (i = 0; i < 3; ++i) {
(function(i){
$.ajax({
type: "POST",
data: "user="+ user,
url: "../php/order_ajax.php",
success: function(data){
$('.obj' + i).html(data);
}
});
})(i);
}