我是从我的Ajax响应得到的[对象的对象。

I'm getting an [object object] from my ajax response.

        $.ajax({
            type: "GET",
            data: "id_1="+id_1+"&id_2="+id_2,
            url:"ajax/url.php"
        }).done(function(data){
            var left= $(data).find("#left");
        $("#left").html(left);
            alert(left);


        });

在我的网址，我只是有一个简单的编码

In my url, I just have a simple coding

if(isset($_GET["id_1"]) && isset($_GET['id_2'])){
    $id_1 = $_GET["id_1"];
    $id_2 = $_GET['id_2'];

    $right= $dbh->prepare("SELECT COUNT(*) FROM table WHERE id_1 = ?");
    $right->execute(array($id_1));
    $left= $dbh->prepare("SELECT COUNT(*) FROM table WHERE id_1 = ? ");
    $left->execute(array($id_2));


    <div id='right'><?php echo $right->fetchColumn();?></div>

    <div id='left'><?php echo $left->fetchColumn();?></div>



}

当我这是所有做的，它提醒回来[对象的对象]

When I this is all done, it alerts back [object object]

谁知道它为什么呢？

谢谢！

编辑：

我添加了一些编码在.done（函数（））

I added some coding in the .done(function())

推荐答案

我已经解决了我的问题。问题是，我需要在另一个缠上了我的div的。在这以后，find（）方法将能够捕捉那些ID的，并返回适当的对象。

I Have solved my problem. The issue was that I needed to wrap my div's within another . After that the find() method would be able to capture those id's and return the proper objects.

if(isset($_GET["id_1"]) && isset($_GET['id_2'])){
    $id_1 = $_GET["id_1"];
    $id_2 = $_GET['id_2'];

    $right= $dbh->prepare("SELECT COUNT(*) FROM table WHERE id_1 = ?");
    $right->execute(array($id_1));
    $left= $dbh->prepare("SELECT COUNT(*) FROM table WHERE id_1 = ? ");
    $left->execute(array($id_2));

<div> // wrapper
    <div id='right'><?php echo $right->fetchColumn();?></div>

    <div id='left'><?php echo $left->fetchColumn();?></div>
</div>



}