我一直在寻找通过这里的问题，并不能找到我终究:(什么一个确切的答案，但我设法得到的东西。

I have been looking through the questions on here and cant find an exact answer to what i am after :( but i have managed to get something.

我有一个表格选择字段这是我从一个数据库查询填充

i have a form select field which i populate from a db query

<select style="width:100%;" class="quform-tooltip chosen-select" id="company_select" name="company_select" title="Company Select" onChange="showUser(this.value)">
<option value="">Please select</option>
<?php
$userID = $user->getUserID();
$query = $user->database->query("SELECT * FROM tbl_businesses as business LEFT JOIN tbl_user_businesses as biz_user ON business.businessID = biz_user.businessID WHERE biz_user.userID ='$userID'");

while($row=$user->database->fetchArray($query))
{
    $bizID = $row['businessID'];
    $bizName = $row['businessName'];
    echo "<option value='$bizID'>$bizName</option>";
}?>
</select>

然后目前有2其他文本框（可能会增加最终），我要填充在上述选择框的值更改/选择

and then there are currently 2 other textboxes (might increase eventually) which i want to populate when the above select box value is changed/selected

<input id="company_name" type="text" name="company_name" value="" />
<input id="company_email" type="text" name="company_email" value="" />

让我有我的选择框的onchange的功能，这是本

so i have an onchange function on my select box which is this

<script>
function showUser(str)
{
if (str=="")
{
    document.getElementById("company_name").innerHTML="";
    return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
    xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
    xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
    if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
        var data = JSON.parse(xmlhttp.responseText);
        for(var i=0;i<data.length;i++) 
        {
          document.getElementById("company_name").innerHTML += data[i].id + ' - ' + data[i].name + ' - ' + data[i].web;
        }
    }
}
xmlhttp.open("GET","formdata.php?q="+str,true);
xmlhttp.send();
}
</script>

和我的formdata.php文件是像这样

and my formdata.php file is like so

    <?php
include("include/user.php");

$q = intval($_GET['q']);

$sql="SELECT * FROM tbl_businesses WHERE businessID = '".$q."'";

$result = $user->database->query($sql);
$info = array();
while($row=$user->database->fetchArray($result))
{
    $cID = $row['bussinessID'];
    $cName = $row['businessName'];
    $cWeb = $row['businessWebsite'];
    $info[] = array( 'id' => $cID, 'name' => $cName, 'web' => $cWeb );
}
echo json_encode($info);?> 

这是正确决策的Ajax调用和返回预期的数据，但我现在需要帮助填充文本框的值？

which is making the ajax call correctly and returning the data expected but i now need help to populate the textbox values?

谁能请帮助我，有literatly花了年龄试图弄明白，林不熟悉JavaScript / JSON所以不知道从哪里开始。

can anyone please help me with this, have literatly spent ages trying to figure it out, im not familiar with javascript/json so not sure where to begin

我想COMPANY_NAME文本框的值设置为$ CNAME;和 company_email文本框的值设置为$ CWEB;

i want the company_name textbox value to be set to $cName; and company_email textbox value to be set to $cWeb;

AP preciate任何帮助

appreciate any help

卢克

推荐答案

OK，我使用的解决方案，为别人想知道我是如何解决它

ok the solution that i used, for anyone else wanting to know how i solved it is

我的index.php包含JavaScript和形式code

my index.php which contains the javascript and the form code

JavaScript的code

javascript code

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js" type="text/javascript"></script>

<script>
function showUser(str)
{
if (str=="")
{
    document.getElementById("company_name").value="";
    return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
    xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
    xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
    if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
        var data = JSON.parse(xmlhttp.responseText);
        for(var i=0;i<data.length;i++) 
        {
          document.getElementById("company_name").value = data[i].name;
          document.getElementById("company_email").value = data[i].web;
        }
    }
}
xmlhttp.open("GET","formdata.php?q="+str,true);
xmlhttp.send();
}
</script>

和形式code

    <select style="width:100%;" class="quform-tooltip chosen-select" id="company_select" name="company_select" title="Company Select" onChange="showUser(this.value)">
<option value="">Please select</option>
<?php
$userID = $user->getUserID();
$query = $user->database->query("SELECT * FROM tbl_businesses as business LEFT JOIN tbl_user_businesses as biz_user ON business.businessID = biz_user.businessID WHERE biz_user.userID ='$userID'");

while($row=$user->database->fetchArray($query))
{
    $bizID = $row['businessID'];
    $bizName = $row['businessName'];
    echo "<option value='$bizID'>$bizName</option>";
}?>
</select>

<input id="company_name" type="text" name="company_name" value="" />
<input id="company_email" type="text" name="company_name" value="" />

然后我formdata.php

then my formdata.php

    $q = intval($_GET['q']);

$sql="SELECT * FROM tbl_businesses WHERE businessID = '".$q."'";

$result = $user->database->query($sql);
$info = array();
while($row=$user->database->fetchArray($result))
{
    $cID = $row['businessID'];
    $cName = $row['businessName'];
    $cWeb = $row['businessWebsite'];
    $info[] = array( 'id' => $cID, 'name' => $cName, 'web' => $cWeb );
}
echo json_encode($info);?> 

完蛋了，感谢charlietfl您的帮助！

thats it, thanks to charlietfl for your help!

希望这可以帮助别人：）

hope this helps someone :)