恐怕只是说我有一个影片剪辑，其中，含有影片剪辑B1，B2，B3，B4，B5

Lest just say i have a movieClip A which contains movieClips B1,B2,B3,B4,B5

我写code下接受一个包含所有影片剪辑和打印一样有名字。

I write code in A to receive all movieclips that a contains and like print there name.

我想这没有更迭：

for each (a:MovieClip in this)
    trace(a.name);

没有人知道如何得到这个工作。

does anyone know how to get this working.

**注意跟踪的名称实际上是一个例子，我想要做的非常不同的事情与物体本身像改变有知名度，这样的**

** note the trace name is actually an example i want to do very different things with the objects itself like changing there visibility and such **

谢谢， Matthy

thanks, Matthy

推荐答案

我不知道如果我完全理解你正在尝试做的，但你可以做这样的事情从父movielcip拉自己的实例名称

I'm not sure if I completely understand what you're trying to do, but you could do something like this to pull their instance names from a parent movielcip:

for(var i:int = 0; i < target_mc.numChildren; i++) {
trace (target_mc.getChildAt(i).name);
}

您也可以拉出更多的信息，如对象的东西种类多一点冗长：

You can also pull out more information such as the type of object with something a little more verbose:

for(var i:int = 0; i < target_mc.numChildren; i++) {
trace ('\t|\t ' +i+'.\t name:' + target_mc.getChildAt(i).name + '\t type:' + typeof 
(target_mc.getChildAt(i))+ '\t' + target_mc.getChildAt(i));
}