我希望能够像做

  VAR XMLQUERY：字符串=a1.a2.a3;
VAR parserVal：XML = parserMethod（XMLQUERY）;
// 要么
VAR parserVal：返回XMLList = parserMethod（XMLQUERY）;`
 

，并得到一个输出类似于

 ＆LT; A3＆GT;有的值小于/ A3＆GT;
 

重要提示：，然后我希望能够更换输出 a1.a2.a3 因此，使用的后裔是毫无疑问的。 ：（

所以它基本上是调用XML查询字符串的能力。有没有办法做到这一点。只是一个提示是超级的，我可以做到这一点，如果我有一点点头开始。

感谢您！

我想我找到与此链接帮助的解决方案：

  

Updating直接在一行中使用ActionScript XML对象中E4X？

 公共静态函数如updateXML（XML：XML，路径：字符串，数据：返回XMLList = NULL，更新：布尔=假，XmlListOnly：布尔=假）：* {
            变种nodesArray：数组= path.split（。）;
            VAR tempXML：XML = XML;
            VAR tempXMLCandidate：XML;
            VAR标签名：字符串;
            对于（VAR我：= 0; I＆LT; nodesArray.length;我++）{
                标签名= nodesArray [I]
                如果（ⅰ== nodesArray.length  -  1）{
                    如果（数据= NULL和放大器;！＆安培;更新和放大器;＆安培;！XmlListOnly）{
                    tempXML [标签名] =数据;
                    }否则，如果（XmlListOnly）{
                        返回tempXML [标签名]。
                    }其他{
                    返回tempXML [标签名] .length（）;
                    }
                }其他{
                    tempXMLCandidate = tempXML [标签名] [0];
                    如果（！tempXMLCandidate）{
                        tempXML.appendChild（tempXMLCandidate）;
                    }
                tempXML = tempXMLCandidate;
                }
            }
            返回tempXML;
        }
 

您可以调用它是这样的：

 如updateXML（xmlHold，words.exercise，sortedXmlList，真正的）;
 

解决方案

我懒得code和测试，但这里的想法：

将您的查询部分a1.a2.a3.split（。） 走在零部件，称 xml.elements（件[I]）（你需要额外的（可能嵌套）函数的递归调用） 如果你得到非空的XMLList，重复调用元素使用下一部分名单上。 在最后一部分，从中提取文本儿童（）[0] 。

I want to be able to do something like

var XMLquery:String = "a1.a2.a3";
var parserVal:XML = parserMethod(XMLquery);
// or
var parserVal:XMLList = parserMethod(XMLquery);`

and get an output something like

<a3>Some value</a3>

Important: And I want to be able to replace the output at a1.a2.a3 so using descendants is out of question. :(

So it's basically the ability to call xml query in string. Is there a way to do this. Just a hint would be super, I can do it if I got a bit of head-start.

Thank you!

I think I found a solution with the help from this link:

Updating an actionscript xml object directly in one line using e4x?

public static function updateXml(xml:XML, path:String, data:XMLList = null,update:Boolean = false,XmlListOnly:Boolean = false):* {
            var nodesArray:Array = path.split(".");
            var tempXML:XML = xml;
            var tempXMLCandidate:XML;
            var tagName:String;
            for (var i:int = 0; i < nodesArray.length; i++){
                tagName = nodesArray[i];
                if (i == nodesArray.length - 1){
                    if (data != null && update && !XmlListOnly){
                    tempXML[tagName] = data;
                    }else if (XmlListOnly){
                        return tempXML[tagName];
                    }else{
                    return tempXML[tagName].length();
                    }
                }else{
                    tempXMLCandidate = tempXML[tagName][0];
                    if (!tempXMLCandidate){
                        tempXML.appendChild(tempXMLCandidate);
                    }
                tempXML = tempXMLCandidate;
                }
            }
            return tempXML;
        }

You can call it like this:

updateXml(xmlHold, "words.exercise", sortedXmlList, true);

解决方案

I'm too lazy to code and test it, but here's idea:

Break your query on parts "a1.a2.a3".split(".") Go on the parts, calling xml.elements(parts[i]) (you'll need extra (maybe nested) function for recursive calls) If you get non-empty XMLList, repeat calling elements on that list using next part. On last part, extract text from it with children()[0].